Answer:
cos 30 + sin60 + sin30 - cos60
we know that sin ( 90 -a ) = cos a { and vice versa }
therefore by using this property,
sin ( 90 - 30 ) + sin 60 + sin 30 - sin ( 90-60)
sin 60 + sin 60 + sin 30 - sin 30 =
<u>2 sin 6</u><u>0</u>
That's the answer I got. Tell me if it's correct
Answer:
j=5√80vπ⁴/2π
Step-by-step explanation:
Take the root of both sides and solve.
j=5√80vπ⁴/2π
-hope it helps
Answer:
1,000,000
Step-by-step explanation: Since there are 10 possible digits, we know that there is a 1/10 chance for any possible digit in any slot. So, since there are 6 slots we can do 1/10^6, or 1 in 1 million.
Answer:
No, it is not a fair game
Step-by-step explanation:
If it was a fair game, the expected value should be 0
If the expected value is 0, then the amount to be won and the amount to be lost is same and thus, the game does not tilt in favor of any of the competitors
But with an expected value of $2, there is actually a favor to one side
The probability of drawing two blue marbles if the first marble is not replaced is 1/5
<h3>How to determine the probabilities?</h3>
<u>The probability of tossing a head and drawing a red marble</u>
The given parameters are:
White = 1
Blue =3
Red = 2
Total = 6
The probability of a head is
P(Head)= 1/2
The probability of drawing a red marble is
P(Red)= 2/6 = 1/3
The required probability is
P = P(Head) * P(Red)
This gives
P = 1/2 * 1/3
P =1/6
<u>The probability of drawing two blue marbles if the first marble is not replaced.</u>
Here, we have:
P(B1) = 3/6 = 1/2
P(B2) = 2/5
The required probability is
P = P(B1) * P(B2)
This gives
P = 1/2 * 2/5
P =1/5
Hence, the probability of drawing two blue marbles if the first marble is not replaced is 1/5
Read more about probability at:
brainly.com/question/24756209
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