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gayaneshka [121]
3 years ago
15

Please help, me I just need to know how to set it up the 2 equation on both.

Mathematics
1 answer:
Ronch [10]3 years ago
7 0
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Find the equation for the horizontal line that goes through point M(a, b).
elena-14-01-66 [18.8K]

Horizontal means zero slope, or a zero coefficient on x.

Answer: y = b



6 0
3 years ago
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What is the solution for r in the following system of equations?<br> 2x + 3y = 16<br> 2 + 2y = 10
klio [65]

Answer:

(2,4)

*View attached graph*

Step-by-step explanation:

2x + 3y = 16

2 + 2y = 10

2 + 2y = 10

-2          - 2

2y = 8

/2  /2

y = 4

2x + 3y = 16

2x + 3(4) = 16

2x + 12 = 16

    - 12   - 12

2x = 4

/2   /2

x = 2

(x,y) -> (2,4)

Hope this helps!

8 0
2 years ago
Consider the similarity transformation of ΔABC to produce ΔEDF.
iogann1982 [59]
ABC rotates 90 degrees clockwise to become EDF.

ABC undergoes transformation of 1/2 so reduces its original size.
6 0
3 years ago
Sam is learning the ancient art of kite making. He has determined that his first kite will have diagonals of 24 inches and 25 in
FromTheMoon [43]

Answer: d

Step-by-step explanation:

4 0
3 years ago
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A 32 foot tall tree casts a shadow that is 48 feet long How far away from the tree is a 6 ft person
dedylja [7]

Answer:

39 feet

Step-by-step explanation:

In the attached diagram

The height of the tree = AB

The height of the man =DE

The length of the shadow =BC

We want to determine how far away from the tree the person is, i.e. |AD|=y

In Triangle ABC

Tan \theta=\dfrac{32}{48}

In Triangle CED

Tan \theta=\dfrac{6}{48-y}

Therefore:

Tan \theta=\dfrac{32}{48}=\dfrac{6}{48-y}\\\dfrac{32}{48}=\dfrac{6}{48-y}\\$Cross Multiply\\32(48-y)=48*6\\1536-32y=288\\32y=1536-288\\32y=1248\\Divide both sides by 32\\y=39

Therefore, the distance of the man from the tree is 39 feet.

7 0
3 years ago
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