All categories

2 years ago

A motor produces 2,500 watts of power. Can it be used to drive a fan that requires 2 ½ horsepower?

Mathematics

1 answer:

ElenaW [278]2 years ago

3 0

9514 1404 393

Answer:

yes

Step-by-step explanation:

A horsepower is on the order of 746 watts*, so 2 1/2 times that will be less than 2500. The motor can be used to drive the fan.

_____

* "horsepower" has several different definitions, depending on the application and the units system being used. All are less than 1000 W, so the above conclusion is valid in any case.

You might be interested in

Maggie graphed the image of a 90 counterclockwise rotation about vertex A of . Coordinates B and C of are (2, 6) and (4, 3) and

Lemur [1.5K]

Answer:

A(2,2)

Step-by-step explanation:

Let the vertex A has coordinates $(x_A,y_A)$

Vectors AB and AB' are perpendicular, then

$\overrightarrow {AB}=(2-x_A,6-y_A)\\ \\\overrightarrow {AB'}=(-2-x_A,2-y_A)\\ \\\overrightarrow {AB}\perp\overrightarrow {AB'}\Rightarrow \overrightarrow {AB}\cdot \overrightarrow {AB'}=0\Rightarrow (2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0$

Vectors AC and AC' are perpendicular, then

$\overrightarrow {AC}=(4-x_A,3-y_A)\\ \\\overrightarrow {AC'}=(1-x_A,4-y_A)\\ \\\overrightarrow {AC}\perp\overrightarrow {AC'}\Rightarrow \overrightarrow {AC}\cdot \overrightarrow {AC'}=0\Rightarrow (4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0$

Now, solve the system of two equations:

$\left\{\begin{array}{l}(2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0\\ \\(4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0\end{array}\right.\\ \\\left\{\begin{array}{l}-4-2x_A+2x_A+x_A^2+12-6y_A-2y_A+y^2_A=0\\ \\4-4x_A-x_A+x_A^2+12-3y_A-4y_A+y_A^2=0\end{array}\right.\\ \\\left\{\begin{array}{l}x_A^2+y_A^2-8y_A+8=0\\ \\x_A^2+y_A^2-5x_A-7y_A+16=0\end{array}\right.$

Subtract these two equations:

$5x_A-y_A-8=0\Rightarrow y_A=5x_A-8$

Substitute it into the first equation:

$x_A^2+(5x_A-8)^2-8(5x_A-8)+8=0\\ \\x_A^2+25x_A^2-80x_A+64-40x_A+64+8=0\\ \\26x_A^2-120x_A+136=0\\ \\13x_A^2-60x_A+68=0\\ \\D=(-60)^2-4\cdot 13\cdot 68=3600-3536=64\\ \\x_{A_{1,2}}=\dfrac{60\pm8}{2\cdot 13}=\dfrac{34}{13},2$

Then

$y_{A_{1,2}}=5\cdot \dfrac{34}{13}-8 \text{ or } 5\cdot 2-8\\ \\=\dfrac{66}{13}\text{ or } 2$

Rotation by 90° counterclockwise about A(2,2) gives image points B' and C' (see attached diagram)

8 0

2 years ago

If the rectangle below is enlarged using a scale

san4es73 [151]

Answer:

The perimeter P of a rectangle is given by the formula, P=2l+2w , where l is the length and w is the width of the rectangle. The area A of a rectangle is given by the formula, A=lw , where l is the length and w is the width.

5 0

2 years ago

The midpoint of GH is (-2,3), and its endpoints are G (g,4) and H (-2,h). What are the values of g and h?

KonstantinChe [14]

Answer:

g =-2

h = 2

Step-by-step explanation:

left end middle right end

G(g,4) (-2,3) (-2,h)

7 0

2 years ago

23/5 as a whole number or mixed number in simplest form and 12/4 whole and mixed numbers and in simplest form 36/6 in whole or m

iren2701 [21]

23/5 = 4 3/5

12/4 = 3

36/6 =6

29/6 = 4 5/6

47/8 =5 7/8

5 0

3 years ago

Read 2 more answers

a farmer examinea sample of 25 egg cartons and finds three cracked eggs whast the best predictions of the number of cartons with

Lana71 [14]

It's C because 500/25 = 20 and 20x3=60

7 0

2 years ago