The answer:
the full question is as follow:
if A+B-C=3pi, then find sinA+sinB-sinC
first, the main formula of sine and cosine are:
sinC = 2sin(C/2)cos(C/2)
sinA +sinB = 2sin[(A+B)/2]cos[(A-B)/2]
therefore:
sinA+sinB-sinC = 2sin[(A+B)/2]cos[(A-B)/2] - 2sin(C/2)cos(C/2)
sin[(A+B)/2] = cos(C/2)
2sin(C/2)cos(C/2) = cos[(A+B)/2
and
A+B-C=3 pi implies A+B =3 pi + C, so
cos[(A+B)/2] = cos [3 pi/2 + C/2]
and with the equivalence cos (3Pi/2 + X) = sinX
sinA+sinB-sinC = cos(C/2)+ sin(C/2)
The bottom trapezoid is
(1/2) * h * (b2 + b1) =
(1/2)*11 * (31+25)
(1/2) * 11 * 56
308
The top parallelogram is
b * h = 12 * 14 = 168
308 +168 = 476 ft^2
Letter B
Answer:
Y = mx + b
y = how far up
x = how far along
m = Slope or Gradient (how steep the line is)
b = value of y when x=0
Answer:
around 8,000
Step-by-step explanation:
its because we can see that it roughly increases and decreases by 2000, its my guess, tell me how u get on
Answer : 1618
Step-by-step explanation: add 128 and 254 together and you get 382. subtract that from 2000.
Final answer : 1618
