You didn't include the formula.
Given that there is no data about the mass, I will suppose that the formula is that of the simple pendulum (which is only valid if the mass is negligible).
Any way my idea is to teach you how to use the formula and you can apply the procedure to the real formula that the problem incorporates.
Simple pendulum formula:
Period = 2π √(L/g)
Square both sides
Period^2 = (2π)^2 L/g
L = [Period / 2π)^2 * g
Period = 3.1 s
2π ≈ 6.28
g ≈ 10 m/s^2
L = [3.1s/6.28]^2 * 10m/s^2 =2.43 m
I hope this helps you.
Answer:
As the sample size is appropriately large, the margin of error is 0.026
Step-by-step explanation:
Answer:
113
Step-by-step explanation:
290 - 64 = 226
226 ÷ 2 = 113
<span>(-7) = e/3 + 14
Subtract 14 on both sides
-7 - 14 = e/3 + 14 - 14
-21 = e/3
Multiply by 3 on both sides
-21 * 3 = e/3 * 3
-63 = e</span>
Answer:
7:11
Step-by-step explanation:
There is no way to simplify the ratio.