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vova2212 [387]
2 years ago
7

PLZZ help im confused

Mathematics
2 answers:
vlabodo [156]2 years ago
6 0

Answer:

12.5

Step-by-step explanation:

12.5+12.5= 25

25+12.5 = 37.5

Alecsey [184]2 years ago
6 0
12.5!!! Hope
This helped you out a bit
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What is the solution 1/x= x+3/2x^2
weqwewe [10]

Answer:

3

Step-by-step explanation:

1/x=x+3/2x²

By cross-multiplication, we get,

2x²=x(x+3)

2x²=x²+3x

2x²-x²-3x=0

x²-3x=0

x(x-3)=0

x=3

8 0
3 years ago
6 to the third power plus 5 (8+1/5
Pani-rosa [81]

Answer:

The answer would be 257

Step-by-step explanation:

7 0
3 years ago
Convert this quadratic to vertex form f(x)=(x-h)^2+k by completing the square. <br> 3x^2-6x+6=0
maria [59]

f(x)=3x^2-6x+6\\\\f(x)=3(x^2-2x)+6\\\\f(x)=3(\underbrace{x^2-2x+1}-1)+6\\\\ f(x)=3[(x-1)^2-1]+6\\\\f(x)=3(x-1)^2-3+6\\\\f(x)=3(x-1)^2+3

6 0
2 years ago
An architect designs rectangular flower garden such that the width is exactly 2/3 of the length. of 290 ft of antique picket fen
kramer

Length (L): L

width (w): (2/3)L

Perimeter (P) = 2L + 2w

               290 = 2(L) + 2(2/3)(L)

               870 = 6L + 4L

               870 = 10L

                87 = L

width (w): (2/3)L   = (2/3)(87)   = 2(29)   = 58

Answer: width = 58 ft, length = 87 ft



6 0
3 years ago
A walking path across a park is represented by the equation y= -3x - 6 . A new path will be built perpendicular to this path. Th
Romashka [77]

Answer:

The equation that represents the new path is y=(1/3)x+4

Step-by-step explanation:

step 1

Find the slope of the give line

we have

y=-3x-6

so

the slope m is equal to

m=-3

step 2

Find the slope of the perpendicular line to the given line

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal of each other

so

we have

m=-3 -----> slope of the given line

therefore

The slope of the perpendicular line is equal to

m=1/3

step 3

With m=1/3 and the point (-3,3) find the equation of the line

y-y1=m(x-x1)

substitute

y-3=(1/3)(x+3)

y=(1/3)x+1+3

y=(1/3)x+4 -----> equation that represent the new path

8 0
3 years ago
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