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Crazy boy [7]
2 years ago
14

PLEASE HELP!!!!!

Mathematics
2 answers:
Vilka [71]2 years ago
6 0
Answer is

<span>b. {(−7,−5),(−3,1),(0,2),(−4,5),(3,−1)}</span>
storchak [24]2 years ago
3 0
Easy. its d, because if u put -7 and {[\72283], it will obviously exclude the factor of 12%[{9293}]. 
You might be interested in
Maria, Denise, and Joseph are making cookies for a bake sale. Maria has 4 times as toany okies for the
ElenaW [278]

Answer:

Maria made 248 cookies, Denise made 62 cookies, Joseph made 372 cookies.

Step-by-step explanation:

Number of cookies made by Maria is m,

made by Denise is d,

made by Joseph is j

We can write the following equations from the word:

m = 4d

j = 6d

m + d + j = 682

We can substitute both 1st and 2nd equation in 3rd and solve for d:

m + d + j = 682

4d + d + 6d = 682

11d = 682

d = 62

Thus,

m = 4(62) = 248

and

j = 6(62) = 372

Maria made 248 cookies, Denise made 62 cookies, Joseph made 372 cookies.

4 0
3 years ago
6x^4-17x^3-7x^2+13x=3 what are all the solutions
wlad13 [49]
6x^4-17x^3-7x^2+13x=3
6x^4-17x^3-7x^2+13x-3=3-3
6x^4-17x^3-7x^2+13x-3=0
y=6x^4-17x^3-7x^2+13x-3
y=0

The solutions are: x=-1, 1/2, 1/3 and 3

8 0
3 years ago
An article in Medicine and Science in Sports and Exercise ["Maximal Leg-Strength Training Improves Cycling Economy in Previously
Sholpan [36]

Answer:

[300.202 , 329.798]

Step-by-step explanation:

The 95% confidence interval is given by the interval

\large [\bar x-t^*\frac{s}{\sqrt n}, \bar x+t^*\frac{s}{\sqrt n}]

where

\large \bar x <em>is the sample mean  </em>

<em>s is the sample standard deviation  </em>

<em>n is the sample size (n = 7)  </em>

\large t^* is the 0.05 (5%) upper critical value for the Student's t-distribution with 6 degrees of freedom (sample size -1), which is <em>an approximation to the Normal distribution for small samples (n<30).</em>

Either by using a table or the computer, we find  

\large t^*= 2.447

and our 95% confidence interval is

\large [315-2.447*\frac{16}{\sqrt{7}}, 315+2.447*\frac{16}{\sqrt{7}}]=\boxed{[300.202,329.798]}

7 0
3 years ago
The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.
Mama L [17]

Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

perimeter of the triangular filed, P = 120 m

length of two known sides, a and b = 21 m and 40 m respectively

The length of the third side is calculated as follows;

a + b + c = P

21 m  + 40 m  + c = 120 m

61 m +  c = 120 m

c = 120 m - 61 m

c = 59 m

                         B

                     ↓            ↓  

                  ↓                          ↓

                ↓                                       ↓

            A →  →  → →  →  → →  → →    →    →  C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0

Angle B is calculated as follows;

Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0

Angle C is calculated as follows;

Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0

Therefore, the largest angle of the field is 149⁰.

       

8 0
3 years ago
Why is it important to calculate the distance between two points on a cartesian coordinate plane?
Gwar [14]

Answer:

Derived from the Pythagorean Theorem, the distance formula is used to find the distance between two points in the plane. The Pythagorean Theorem,

a

2

+

b

2

=

c

2

, is based on a right triangle where a and b are the lengths of the legs adjacent to the right angle, and c is the length of the hypotenuse. The relationship of sides

|

x

2

−

x

1

|

and

|

y

2

−

y

1

|

to side d is the same as that of sides a and b to side c. We use the absolute value symbol to indicate that the length is a positive number because the absolute value of any number is positive. (For example,

|

−

3

|

=

3

. ) The symbols

|

x

2

−

x

1

|

and

|

y

2

−

y

1

|

indicate that the lengths of the sides of the triangle are positive. To find the length c, take the square root of both sides of the Pythagorean Theorem.

c

2

=

a

2

+

b

2

→

c

=

√

a

2

+

b

2

It follows that the distance formula is given as

d

2

=

(

x

2

−

x

1

)

2

+

(

y

2

−

y

1

)

2

→

d

=

√

(

x

2

−

x

1

)

2

+

(

y

2

−

y

1

)

2

We do not have to use the absolute value symbols in this definition because any number squared is positive.

A GENERAL NOTE: THE DISTANCE FORMULA

Given endpoints

(

x

1

,

y

1

)

and

(

x

2

,

y

2

)

, the distance between two points is given by

d

=

√

(

x

2

−

x

1

)

2

+

(

y

2

−

y

1

)

2

Step-by-step explanation:

4 0
3 years ago
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