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taurus [48]
3 years ago
14

find the sale price of the item. round to two decimal places if necessary original price $225.60 markdown 80 %

Mathematics
1 answer:
IgorC [24]3 years ago
6 0

Answer:

gan if you could anssbdhe

Step-by-step explanation:

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Mariana [72]
A square root is a number that produces a specific number when multiplied by itself. Basically it's the same number multiplied by itself.
hope this helps:)
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4 years ago
Read 2 more answers
Can someone help pleas
Lena [83]

Step-by-step explanation:

According to picture 1, it is <u>A. </u><u>corresponding.</u>

Also according to picture 2, it is <u>E.</u><u> </u><u>same </u><u>side</u><u> </u><u>interior.</u>

And according to picture 3, it is <u>D.</u><u> </u><u>vertical</u>

6 0
3 years ago
Dan's school is selling tickets to a play. On the first day of ticket sales the school sold 1 adult ticket and 6 student tickets
VashaNatasha [74]

Answer:

Let's define the variables:

A = price of one adult ticket.

S = price of one student ticket.

We know that:

"On the first day of ticket sales the school sold 1 adult ticket and 6 student tickets for a total of $69."

1*A + 6*S = $69

"The school took in $150 on the second day by selling 7 adult tickets and student tickets"

7*A + 7*S = $150

Then we have a system of equations:

A + 6*S = $69

7*A + 7*S = $150.

To solve this, we should start by isolating one variable in one of the equations, let's isolate A in the first equation:

A = $69 - 6*S

Now let's replace this in the other equation:

7*($69 - 6*S) + 7*S = $150

Now we can solve this for S.

$483 - 42*S + 7*S = $150

$483 - 35*S = $150

$483 - $150 = 35*S

$333 = 35*S

$333/35 = S

$9.51 = S

That we could round to $9.50

That is the price of one student ticket.

4 0
3 years ago
Which is an x-intercept of the graphed function?<br> O (0,4)<br> O(-1,0)<br> O (4, 0)<br> O (0,-1)
dolphi86 [110]

Answer:

(x, y)

(-1,0)

since the rest of the points aren't in the multiple choice well it's (-1,0)

3 0
3 years ago
PLEASE HELP ASAP WILL GIVE BLAINLY PTS
ddd [48]

Answer:

\large\boxed{C.\ \dfrac{2x-20}{x^2+6x-40}}

Step-by-step explanation:

f(x)=\dfrac{x-16}{x^2+6x-40}=\dfrac{x-16}{x+10x-4x-40}=\dfrac{x-16}{x(x+10)-4(x+10)}\\\\f(x)=\dfrac{x-16}{(x-4)(x+10)}\\\\g(x)=\dfrac{1}{x+10}\\\\f(x)+g(x)=\dfrac{x-16}{(x-4)(x+10)}+\dfrac{1}{x+10}=\dfrac{x-16}{(x-4)(x+10)}+\dfrac{1(x-4)}{(x-4)(x+10)}\\\\=\dfrac{x-16+x-4}{(x-4)(x+10)}=\dfrac{2x-20}{(x-4)(x+10)}=\dfrac{2x-20}{x^2+6x-40}

4 0
3 years ago
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