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Sphinxa [80]
3 years ago
8

Can someone help pleas

Mathematics
1 answer:
Lena [83]3 years ago
6 0

Step-by-step explanation:

According to picture 1, it is <u>A. </u><u>corresponding.</u>

Also according to picture 2, it is <u>E.</u><u> </u><u>same </u><u>side</u><u> </u><u>interior.</u>

And according to picture 3, it is <u>D.</u><u> </u><u>vertical</u>

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Please help and show your work . Thanks if the picture is upside down turn your device on portrait by locking it so it won't tur
Bezzdna [24]
So we know that the bag has total 15 cookies, and 1 cookie that does not have any raisin. Finally, the probability that one cookie won't have any raisin is 1/15 or 7 percent. Hope it help!
3 0
3 years ago
Fine -x when x = -17
Rashid [163]

Answer:

17

Step-by-step explanation:

-(-17)= 17

3 0
3 years ago
Which statement is true about the difference 2 square root of 7 − square root of 26?
lora16 [44]

2√7 - √26 ≈ 5.29150262213... - 5.09901951359...

... ≈ 0.19248310854...

The result is an irrational number not described by any of your answer selections.

None of the statements is true.

7 0
3 years ago
What is 1/5 ÷ 5<br> someone pls help me
Elena-2011 [213]

Answer: 1/25 or 0.04

Step-by-step explanation:

1/5 divided by 5 for the whole number you have to turn it to a fraction so you would do 5/1

THEN: it becomes 1/5 divided by 5/1 but you have to do the inverse so the inverse of division is multiplying and you will cross multiply so 5*5= 25 and 1*1=1 therefor the final answer is 1/25

5 0
2 years ago
Read 2 more answers
Suppose your boss wants you to obtain a sample to estimate a population mean. Based on previous analyses, you estimate that 49 i
VashaNatasha [74]

Answer:

the minimum sample size n = 11.03

Step-by-step explanation:

Given that:

approximate value of the population standard deviation \sigma = 49

level of significance ∝ = 0.01

population mean = 38

the minimum sample size n = ?

The minimum sample size required can be determined by calculating the margin of error which can be re[resented by the equation ;

Margin of error = Z_{ \alpha /2}} \times \dfrac{\sigma}{\sqrt{n}}

38 = \dfrac{2.576 \times 49}{\sqrt{n}}

\sqrt{n} = \dfrac{2.576 \times 49}{38}

\sqrt{n} = \dfrac{126.224}{38}

\sqrt{n} = 3.321684211

n= (3.321684211)^2

n ≅ 11.03

Thus; the minimum sample size n = 11.03

5 0
3 years ago
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