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Sphinxa [80]
3 years ago
8

Can someone help pleas

Mathematics
1 answer:
Lena [83]3 years ago
6 0

Step-by-step explanation:

According to picture 1, it is <u>A. </u><u>corresponding.</u>

Also according to picture 2, it is <u>E.</u><u> </u><u>same </u><u>side</u><u> </u><u>interior.</u>

And according to picture 3, it is <u>D.</u><u> </u><u>vertical</u>

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Divide 120 in the ratio of 1:2
mestny [16]

Answer:

40:80

Step-by-step explanation:

x+2x=3x

3x=120

120/3=

40

40*2=80

40:80=1:2

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3 years ago
Which inequality's graph will have a dashed boundary line?
irakobra [83]
THE EQUALITY WITH BOUNDARY IS B

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3 years ago
Solve using law of sines or law of cosines!
malfutka [58]

Answer:

Part 5) The length of the ski lift is 1.15\ miles

Part 6) The height of the tree is 18.12 m

Step-by-step explanation:

Part 5)

Let

A -----> Beginning of the ski lift

B -----> Top of the mountain

C -----> Base of mountain

we have

b=0.75\ miles

A=20\°

C=180\°-50\°=130\° ----> by supplementary angles

Find the measure of angle B

Remember that the sum of the interior angles must be equal to 180 degrees

B=180\°-A-C

substitute

B=180\°-20\°-130\°=30\°

Applying the law of sines

\frac{b}{sin(B)}=\frac{c}{sin(C)}

substitute

\frac{0.75}{sin(30\°)}=\frac{c}{sin(130\°)}

c=\frac{0.75}{sin(30\°)}(sin(130\°))

c=1.15\ miles

Par 6)

see the attached figure with letters to better understand the problem

<u><em>Applying the law of sines in the right triangle BDC</em></u>

In the right  triangle BDC 20 degrees is the complement of 70 degrees

\frac{BC}{sin(70\°)}=\frac{x}{sin(20\°)}

BC=(sin(70\°))\frac{x}{sin(20\°)} -----> equation A

<u><em>Applying the law of sines in the right triangle ABC</em></u>

In the right  triangle ABC 50 degrees is the complement of 40 degrees

\frac{BC}{sin(40\°)}=\frac{x+15}{sin(50\°)}

BC=(sin(40\°))\frac{x+15}{sin(50\°)} -----> equation B

Equate equation A and equation B and solve for x

(sin(70\°))\frac{x}{sin(20\°)}=(sin(40\°))\frac{x+15}{sin(50\°)}\\\\2.7475x=0.8391(x+15)\\\\2.7475x=0.8391x+12.5865\\\\2.7475x-0.8391x=12.5865\\\\x=6.60\ m

<u><em>Find the value of BC</em></u>

BC=(sin(70\°))\frac{6.6}{sin(20\°)}

BC=18.12\ m

therefore

The height of the tree is 18.12 m

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Which of the expressions are equivalent to the one below? Check all that apply.
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D and a because they both dont change the answer and b 
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