Answer:
7,000,000,000
Step-by-step explanation:
since the closest number is less than 5 (1<5) you round down making the nearest billion 7
Answer:
Step-by-step explanation:
OS ≅ OU, so we will set those 2 expressions equal to each other and solve for y:
6y = 42 so
y = 7
Same goes for OT and OV:
x + 5 = 23 so
x = 18 and
SU = 84
Probably Erica is charging 150% of the first month of rental/leasing an apartment.
$850 being 150% of the rental/ lease for a month
the amount Erica's fee is based is $850×100:150=$566.(6)
Answer:
Final answer is
.
Step-by-step explanation:
Given expression is 
Now we need to find about what is product of both factors.
We see that both factors are in exponent form having equal base "x".
So we can apply formula: 





Hence final answer is
.
Answer:
z = 21 ; y= 16
Step-by-step explanation:
first of all we have to isolate a variable.
In second expression we can obtain:
3y = 2z+6
y = 2/3 z + 2
now we have to substitute this value in the first equation and solve it
8(2/3z+2)-5z = 23
16/3z + 16 -5z = 23
16z +48 - 15z = 69
z = 21
now we have to substitute z in the second equation:
y = 2/3 (21) +2
y = 14+ 2 = 16
y = 16