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atroni [7]
2 years ago
15

A city planner is rerouting traffic in order to work on a stretch of road. The equation of the path of the old route can be desc

ribed as y = 2/5x− 4. What should the equation of the new route be if it is to be perpendicular to the old route and will go through point (P, Q)?
y − Q = -5/2(x − P)

y − Q = 2/5(x − P)

y − P = -5/2(x − Q)

y − P = 2/5(x − Q)
Mathematics
1 answer:
g100num [7]2 years ago
5 0

Answer:

y - Q = -5/2(x - P)

Step-by-step explanation:

The equation of a line in point slope form is expressed as y - y0 = m(x-x0)

(x0, y0) is the point

m is the slope

Given the equation

y = 2/5x− 4.

Slope m  = 2/5

Slope of the perpendicular line = -1/(2/5) = -5/2

Point;

x0 = P

y0 = Q

Substitute into the formula;

y - y0 = m(x-x0)

y - Q = -5/2(x - P)

This gives the required equation

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Step-by-step explanation:

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Quadratic formula

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If z is inversely proportional to r, and z= 32 when r=1.5, find r when z=8.
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Read 2 more answers
After being rejected for employment, Kim Kelly learns that the Bellevue Credit Company has hired only five women among the last
Georgia [21]

Answer:

The probability that 5 or fewer women are hired, assuming no gender discrimination, is 0.0317; we can use this result to support her charge of gender discrimination.

Step-by-step explanation:

If we are assuming that the women and the men are equally qualified, then the probability for each employee that is hired the probability for it to be a women should be 1/2. Note that the fact that more men that women are hired in a sample might not be disctrimination: for example, if 2 men are hired out of 2 employees, that can happen with probability 1/4, so it is quite common. In order to support her charge for gender discrimination, we need at least a probability less that 0.05 that 5 (or less) women are hired out of 19 employees.

Since each configuration is equally probable, we will count the total amount of possible cases that 5 or less women are hired, and dividide it by the total amount of cases, 2¹⁹.

  • 0 women hired: one possible case: every employee is male
  • 1 women hired: 19 possible cases
  • 2 women hired: {19 \choose 2} = 171 possible cases
  • 3 women hired: {19 \choose 3}  = 969 possible cases
  • 4 women hired: {19 \choose 4} = 3876 possible cases
  • 5 women hired: {19 \choose 5} = 11628 possible cases

Thus, there are a total of 11628+3876+969+171 = 16644 possible cases out of 2¹⁹ ones. All of them with seemingly equal probability. As a consequence, the probability of 5 or less women to be hired out of 19 employees, assuming that the probability to hire 1 is 1/2, is

16644/2¹⁹ = 0.0317 < 0.05

The probability that 5 or fewer women are hired, assuming no gender discrimination, is 0.0317. Since the probability is so low, we can conclude that for the employer, a woman equally qualified as a man is less likely to be hired, therefore, we can support her charge of gender discrimination.

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3 years ago
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