A.) To find the maximum height, we can take the derivative of h(t). This will give us the rate at which the horse jumps (velocity) at time t.
h'(t) = -32t + 16
When the horse reaches its maximum height, its position on h(t) will be at the top of the parabola. The slope at this point will be zero because the line tangent to the peak of a parabola is a horizontal line. By setting h'(t) equal to 0, we can find the critical numbers which will be the maximum and minimum t values.
-32t + 16 = 0
-32t = -16
t = 0.5 seconds
b.) To find out if the horse can clear a fence that is 3.5 feet tall, we can plug 0.5 in for t in h(t) and solve for the maximum height.
h(0.5) = -16(0.5)^2 + 16(-0.5) = 4 feet
If 4 is the maximum height the horse can jump, then yes, it can clear a 3.5 foot tall fence.
c.) We know that the horse is in the air whenever h(t) is greater than 0.
-16t^2 + 16t = 0
-16t(t-1)=0
t = 0 and 1
So if the horse is on the ground at t = 0 and t = 1, then we know it was in the air for 1 second.
Answer:
<h2>Below, Hope this helps :)</h2>
Step-by-step explanation:
The variable t represents the amount of gas in mom's truck. Since we need to find a number that is 50% more than 12, we use 1.5 (we would use 2 if we want 100% more, so it makes sense that we use 1.5, since we want to add 1/2 of 12 to 12. The answer is 18.)
We are given
area of sphere is 200.96cm^2
it means that we are given surface area
so, we can use surface area formula
where S is surface area
r is radius
so, firstly we need to find radius or r
we can solve for r
now, we can find volume
we can plug r
now, we can find volume
.............Answer
Answer:
16 cm2
Step-by-step explanation:
By equa tion of area of triangle: S = 1/2 * height * base
Triangle B: 32 = 1/2 * 8 * x --> x = 8 (cm)
The base of triangle A is half of the base of triangle B so it is 4 cm.
The area of triangle A = 1/2 * 8 * 4 = 16 (cm2)
The answer to the question above is letter C. To explain the answer if the given question, a circle of 30 inches radius, if the central angle is 35 degrees, intersecting the circle forms an arc of length which is 18.33 inches.
