All categories

3 years ago

How many swimmers are there represented on this dot plot?

Mathematics

2 answers:

algol133 years ago

8 0

6/24 is the answer for this solution

vazorg [7]3 years ago

6 0

Answer:

424

Step-by-step explanation:

just add as many numbers on the bottom of the line on that specific dot plus the amount on it to get your answer for each then add them all together to get your answer

You might be interested in

Matt made a 75% on his test. There were 20 questions on the test. How many

GaryK [48]

Answer:

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Three times a number, subtracted from 20, is equal to -7

tia_tia [17]

The answer is 20-3x=-7 explanation

4 0

3 years ago

Help pleaseeee!!!!!!!!! I’ll mark brainliest!!!!!

Margarita [4]

Answer:

i believe it is D side angle side

Step-by-step explanation:

7 0

3 years ago

Determine if (2, 9) is a solution to the following system. y = 3x+3 y = x+9 a Yes b No

vagabundo [1.1K]

Answer:

B)no

Step-by-step explanation:

the correct solution is (3,12)

8 0

3 years ago

An Airliner has a capacity for 300 passengers. If the company overbook a flight with 320 passengers, What is the probability tha

TEA [102]

Answer:

The probability is $P(X >300 ) = 0.97219$

Step-by-step explanation:

From the question we are told that

The capacity of an Airliner is k = 300 passengers

The sample size n = 320 passengers

The probability the a randomly selected passenger shows up on to the airport

$p = 0.96$

Generally the mean is mathematically represented as

$\mu = n* p$

=> $\mu = 320 * 0.96$

=> $\mu = 307.2$

Generally the standard deviation is

$\sigma = \sqrt{n * p * (1 -p ) }$

=> $\sigma = \sqrt{320 * 0.96 * (1 -0.96 ) }$

=> $\sigma =3.50$

Applying Normal approximation of binomial distribution

Generally the probability that there will not be enough seats to accommodate all passengers is mathematically represented as

$P(X > k ) = P( \frac{ X -\mu }{\sigma } > \frac{k - \mu}{\sigma } )$

Here $\frac{ X -\mu }{\sigma } =Z (The \ standardized \ value \ of \ X )$

=> $P(X >300 ) = P(Z > \frac{300 - 307.2}{3.50} )$

Now applying continuity correction we have

$P(X >300 ) = P(Z > \frac{[300+0.5] - 307.2}{3.50} )$

=> $P(X >300 ) = P(Z > \frac{[300.5] - 307.2}{3.50} )$

=> $P(X >300 ) = P(Z > -1.914 )$

From the z-table

$P(Z > -1.914 ) = 0.97219$

$P(X >300 ) = 0.97219$

8 0

3 years ago