What form of a quadratic function would be graphed if the vertex at the same point as the y-intercept?
1 answer:
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Work backwards.
s=ut+(at^2)/2
Subtract ut.
s-ut=(at^2)/2
Multiply by 2.
2(s-ut)=at^2
Divide by a.
2(s-ut)/a=t^2
Find the square root:
s=ut+(at^2)/2
Subtract ut.
s-ut=(at^2)/2
Multiply by 2.
2(s-ut)=at^2
Divide by a.
2(s-ut)/a=t^2
Find the square root: