Answer:
E, A, F, A
Step-by-step explanation:
A,A
B,A
C,A
D,A
E,A
F,A
A) For this problem, we will need to use a normal calculation, in that we find the z-score and the area to the right using Table A.
z = (10 - 7.65) / 1.45
z = 1.62
area to the left for a z-score of 1.62 = 0.9474
area to the right for a z-score of 1.62 = 0.0526
The probability that a randomly selected ornament will cost more than $10 is 0.0526 or 5.26%.
B) For this problem, we will use the binomial probability formula since the problem is asking for the probability that exactly 3 ornaments cost over $10. There are two forms of this equation. One is <em>nCr x p^r x q^n-r</em> and the other is <em>(n r) x p^r x (1 - p)^n-r</em>. I will show both formulas below.
8C3 x 0.0526^3 x 0.9474^5
(8 3) x 0.0526^3 x 0.9474^5
With both equations, the answer is the same. Whichever you are more familiar or comfortable with is the one I would recommend you use.
The probability that exactly 3 of the 8 ornaments cost over $10 is 0.00622 or 0.622%.
Hope this helps!! :)
135 mph
because if i divide 270/2 it gives me 135
hope this helps.
Answer:
The speed of plane is
, and speed wind is
.
Step-by-step explanation:
Given against the wind the airline flew
miles in
hours.
including the tailwind the return trip took
hours.
Let speed of plane is
.
Also, speed of the wind is
.
Now, we will find speed on each case.
Speed against the wind is 
Speed with the wind is 
Now, we will write the equation

Add these equation we get,

Now, plug this value in
to get speed of wind

So, the speed of plane in still air is
, and speed of the wind is
.
The key thing to look for to determine whether a sequence is geometric is to see whether the ratio between consecutive terms - the number I would multiply one term by to get the next - is constant.
By inspection, we see that the fourth answer choice satisfies that, as
Why not the first? We have 
The third choice is not a geometric sequence, but rather an arithmetic sequence, where the difference between consecutive terms is constant. Just to make sure that it isn't geometric, we compute 
The second sequence is not geometric (although it does eventually converge to 1, but not its corresponding series), as 