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yan [13]
4 years ago
9

Which of the following is a geometric sequence?

Mathematics
1 answer:
anastassius [24]4 years ago
8 0

The key thing to look for to determine whether a sequence is geometric is to see whether the ratio between consecutive terms - the number I would multiply one term by to get the next - is constant.

By inspection, we see that the fourth answer choice satisfies that, as \frac{81}{27}=\frac{27}{9}=\frac{9}{3}=\frac{3}{1}=3. Why not the first? We have 2=\frac{12}{6}\ne\frac{6}{2}=3.

The third choice is not a geometric sequence, but rather an arithmetic sequence, where the difference between consecutive terms is constant. Just to make sure that it isn't geometric, we compute \frac{14}{9}\ne\frac{9}{4}.

The second sequence is not geometric (although it does eventually converge to 1, but not its corresponding series), as \frac{4}{3}=\frac{2/3}{1/2}\ne\frac{3/4}{2/3}=\frac{9}{8}.

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t - 3 ≤ 12

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Answer:

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