Answer:
31.3 feet
Step-by-step explanation:
-23.6+13.4 = -10.2
-10.2 - 21.1 = -31.3
Answer:
<h2>2/5</h2>
Step-by-step explanation:
The question is not correctly outlined, here is the correct question
<em>"Suppose that a certain college class contains 35 students. of these, 17 are juniors, 20 are mathematics majors, and 12 are neither. a student is selected at random from the class. (a) what is the probability that the student is both a junior and a mathematics majors?"</em>
Given data
Total students in class= 35 students
Suppose M is the set of juniors and N is the set of mathematics majors. There are 35 students in all, but 12 of them don't belong to either set, so
|M ∪ N|= 35-12= 23
|M∩N|= |M|+N- |MUN|= 17+20-23
=37-23=14
So the probability that a random student is both a junior and social science major is
=P(M∩N)= 14/35
=2/5
And you know right this girl has how many years of the first type of quantity of correspond to one unit of the second type of quantity
Answer:
Lane Viking's Score is 17
Black Eagles's Score is 21
Step-by-step explanation:
Let Lane Viking's Score be x and Black Eagles's Score be y.
Black Eagles's Score = 4+ Lane Viking's Score
so y = 4 + x (Equation 1)
Total Score = 38
Black Eagles's Score + Lane Viking's Score = 38
so y + x =38 (Equation 2)
Putting y's value from Equation 1 in Equation 2
4 + x + x = 38
2x = 38-4
x=34/2
x=17
Putting value of x in Equation 1
y = 4 + 17
y = 21
