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notsponge [240]
3 years ago
8

What greater than 476 and less than 598​

Mathematics
2 answers:
Anarel [89]3 years ago
8 0

Answer:

Any numbers 477 to 597

I could pick 500 i mean its greater than 476 and less that 598.

Most likely I would pick 597 because its close.

hichkok12 [17]3 years ago
7 0
597 I’m pretty sure
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Solve for t if p≠q<br> (t+p)/q - q/p = (t-q)/p + p/q
german

Answer:

.. q T 0 = (q/p)a (q/p)a − (q/p)T−10 if p ≠ q and qT0 = 1 − T0/a if p = q = 1/2.

Step-by-step explanation:

Suppose that there are two different solutions, p and q, in [a, b]. Thus p =g(p) q =g(q) p ≠ q The function g(x) satisfies the hypotheses of the mean-value ... that g(p) –g(q) = (p – q) g׳(t) Because g(p) =p and g(q) = q, the left side of Eq. (1-3) may...

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3 years ago
55 employees increased by 20 percent<br>please help!​
Rama09 [41]

Answer:

I believe its 66

Step-by-step explanation:

55×20%=11

55+11=66

4 0
3 years ago
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It cost $13.50 to but 3 used video games how much will it cost to buy 1
fomenos

Answer:

4.50

Step-by-step explanation:

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3 years ago
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Each of these extreme value problems has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to f
tino4ka555 [31]

Answer:

The minimum value of the given function is f(0) = 0

Step-by-step explanation:

Explanation:-

Extreme value :-  f(a, b) is said to be an extreme value of given function 'f' , if it is a maximum or minimum value.

i) the necessary and sufficient condition for f(x)  to have a maximum or minimum at given point.

ii)  find first derivative f^{l} (x) and equating zero

iii) solve and find 'x' values

iv) Find second derivative f^{ll}(x) >0 then find the minimum value at x=a

v) Find second derivative f^{ll}(x) then find the maximum value at x=a

Problem:-

Given function is f(x) = log ( x^2 +1)

<u>step1:</u>- find first derivative f^{l} (x) and equating zero

  f^{l}(x) = \frac{1}{x^2+1} \frac{d}{dx}(x^2+1)

f^{l}(x) = \frac{1}{x^2+1} (2x)  ……………(1)

f^{l}(x) = \frac{1}{x^2+1} (2x)=0

the point is x=0

<u>step2:-</u>

Again differentiating with respective to 'x', we get

f^{ll}(x)=\frac{x^2+1(2)-2x(2x)}{(x^2+1)^2}

on simplification , we get

f^{ll}(x) = \frac{-2x^2+2}{(x^2+1)^2}

put x= 0 we get f^{ll}(0) = \frac{2}{(1)^2}   > 0

f^{ll}(x) >0 then find the minimum value at x=0

<u>Final answer</u>:-

The minimum value of the given function is f(0) = 0

5 0
4 years ago
5g + 7g and g(5 + 7) when g=6
oksian1 [2.3K]

Answer:

Value of equation = 144

Step-by-step explanation:

Given:

5g + 7g + g(5 + 7)

when g = 6

Find:

Value of equation

Computation:

5g + 7g + g(5 + 7)

5g + 7g + g(12)

5(6) + 7(6) + (6)(12)

30 + 42 + 72

Value of equation = 144

4 0
3 years ago
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