Answer:
The common ratio is 5 and the 5th term is 1250
Step-by-step explanation:
The common ratio is given by
r=U(2)/U (1)
=10/2
=5
The fifth term
U (n)=ar^n-1
U(5)=2(5)^5-1
=2×5^4
=2×625
=1250
Answer:
The 20th percentile of coffee temperature is 155.4532 degrees Fahrenheit.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 160 degrees
Standard Deviation, σ = 5.4 degrees
We are given that the distribution of temperature of coffee is a bell shaped distribution that is a normal distribution.
Formula:
We have to find the value of x such that the probability is 0.2
Calculation the value from standard normal z table, we have,
Thus,
The 20th percentile of coffee temperature is 155.4532 degrees Fahrenheit.
Answer:
Step-by-step explanation:
In the model
Log (salary) = B0 + B1LSAT +B2GPA +B3log(libvol) +B4log(cost)+B5 rank+u
The hypothesis that rank has no effect on log (salary) is H0:B5 = 0. The estimated equation (now with standard errors) is
Log (salary) = 8.34 + .0047 LSAT + .248 GPA + .095 log(libvol)
(0.53) (.0040) (.090) (.033)
+ .038 log(cost) – .0033 rank
(.032) (.0003)
n = 136, R2 = .842.
The t statistic on rank is –11(i.e. 0.0033/0.0003), which is very significant. If rank decreases by 10 (which is a move up for a law school), median starting salary is predicted to increase by about 3.3%.
(ii) LSAT is not statistically significant (t statistic ≈1.18) but GPA is very significance (t statistic ≈2.76). The test for joint significance is moot given that GPA is so significant, but for completeness the F statistic is about 9.95 (with 2 and 130 df) and p-value ≈.0001.
Answer:
y = (3/2)x2 - (9/2)x+ 9
Step-by-step explanation:
