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2 years ago

17)

Mathematics

2 answers:

DanielleElmas [232]2 years ago

7 0

Answer:

B) 6

Step-by-step explanation: g = x - 9, g = 15 - 9. 15 - 9 = 6.

Anna35 [415]2 years ago

6 0

<u>Answer:</u>

<h2>B.</h2><h2 /><h3>Explanation:</h3><h3 />

<u>We start with </u>

g = x - 9

<u />

g = 15 - 9

15-9=

So, g = 6

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Recall the experiment comparing patients 4 weeks after surgery for carpal

dimulka [17.4K]

Answer:

4. H0: u1= u2 Ha; u1≠ u2

5. The smaller value of p supports the null hypothesis.

Step-by-step explanation:

4. The null and alternate hypotheses are

H0: u1= u2 i.e there no difference between the mean pinch strengthof the two surgeries

against the claim

Ha; u1≠ u2 i.e there a difference between the mean pinch strengthof the two surgeries

It can be written like this as well

H0: u1 -u2= 0 i.e there no difference between the mean pinch strengthof the two surgeries

against the claim

Ha; u1 -u2≠ 0 i.e there a difference between the mean pinch strengthof the two surgeries

Part 5. The test having a p- value less than 0.05 tells that the null hypothesis cannot be rejected. Theres no evidence to reject the null hypothesis.

The smaller value of p supports the null hypothesis.

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2 years ago

Jim's backyard is a rectangle that is 15 5/6 yards long and 10 2/5 yards wide. Jim buys sods in pieces that are 1 1/3 yards long

Ne4ueva [31]

We are given

Jim's backyard:

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$L=15\frac{5}{6} =\frac{95}{6} yards$

width is

$W=10\frac{2}{5} =\frac{52}{5} yards$

Since, this is rectangle

so, we can find area of rectangle

$A=L*W$

$A=(\frac{95}{6})*(\frac{52}{5})$

$A=\frac{494}{3} yard^2$

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length is

$l=1\frac{1}{3} =\frac{4}{3} yards$

width is

$w=1\frac{1}{3} =\frac{4}{3} yards$

Since, it is rectangle in shape

so,

$Area=l*w$

$A=\frac{4}{3}*\frac{4}{3}$

$A=\frac{16}{9}yard^2$

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$N=\frac{\frac{494}{3} }{\frac{16}{9} }$

now, we can simplify it

$N=\frac{741}{8}$ pieces need ..............Answer

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3 years ago

How to find the area of a triangle with only the radius?

Darya [45]

Divide the bh by 1/2

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3 years ago

Two sections of a class took the same quiz. Section A had 15 students who had a mean score of 80, and Section B had 20 students

Nezavi [6.7K]

Answer: A. 85.7

Step-by-step explanation:

Given : Two sections of a class took the same quiz.

Section A had 15 students who had a mean score of 80, and Section B had 20 students who had a mean score of 90.

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Then , for section A :

$\text{Mean score }=\dfrac{\text{Sum of scores in sec A}}{\text{No. of students}}$

$\Rightarrow\ 80=\dfrac{\text{Sum of scores in sec A}}{15}\\\\\Rightarrow\ \text{Sum of scores in sec A}=80\times15=1200$

Similarly in Section B, $\text{Sum of scores in sec B}=90\times20=1800$

Total scores = Sum of scores in sec A+Sum of scores in sec B

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Total students = Students in sec A +Students in sec B

=15+20=35

Now , the mean score for all of the students on the quiz = $\dfrac{\text{Total score}}{\text{Total students}}$

$=\dfrac{3000}{35}=85.7142857143\approx85.7$

Hence, the approximate mean score for all of the students on the quiz = 85.7

Thus , the correct answer is option A. 85.7.

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2 years ago

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Hatshy [7]

Answer:

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Step-by-step explanation:

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3 years ago