Evaluate the given expression and express the result using the usual format for writing numbers (instead of scientific notatio
n). 29 Upper C 329C3 29 Upper C 329C3equals=nothing
1 answer:
Answer:
29C3 = 3654
Step-by-step explanation:
What is applied here is combination that n - combination of r which is a subscript and the n - is a superscript.
- nCr = nPr/r!
- where nPr = n!/(n-r)!
- nCr = n!/(n-r)! r!
- And we are told to find 29C3, apply the formula and your results will be out.
Attached is the detailed explanation.
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The answer is a =
Step-by-step explanation:
<em>1. Convert the mixed fraction to an improper fraction</em>
To find the numerator, multiply the denominator by the whole number and add the numerator to it.
The denominator remains the same.
So, 2 will be
<em>2. Now the equation is,</em>
a -
a =
+
a
<em>3. Take LCM on both sides. </em>
For the left side, multiply the first fraction by and multiply the second fraction by
a -
a =
<em>4. Solve by making a the subject</em>
=
=
=10+8a
= 10 + 8a
a = 2(10 + 8a)
a = 20 + 16a
a-16a = 20
-15a = 20
a =
a =
Therefore, the answer is a =
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Answer:
The correct options are:
Option B) is never zero.
Option F) When x=0, y≠0
Step-by-step explanation:
Consider the provided function.
When we substitute x=0 in above function we get:
When we substitute x=-1 in above function we get:
When we substitute x=1 in above function we get:
The above function is exponential function which does not pass through the origin and the range of the function is a positive number.
The graph of the function is shown in figure 1.
Now consider the provided options.
Option A) is always greater than or equal to 1.
The option is incorrect as the value of the function is less than 1 for negative value of x.
Option B) is never zero
The option is correct.
Option C) When y=0, x=0
The option is incorrect.
Option D) When x=0, y=4
When x=0 the value of y is 1.
Thus, the option is incorrect.
Option E) is zero when x=0
When x=0 the value of is 1.
Thus, the option is incorrect.
Option F) When x=0, y≠0
The option is correct as 0≠1.
