Step-by-step explanation:
If a variables varies jointly, we can just divide it by the other variables in relation to it.
For example, since p variables jointly as q and square of r, then
![\frac{p}{q {r}^{2} } = k](https://tex.z-dn.net/?f=%20%5Cfrac%7Bp%7D%7Bq%20%7Br%7D%5E%7B2%7D%20%7D%20%20%3D%20k)
where k is a constant
First, let find k. Substitute p= 200
q= 2, and r=3.
![\frac{200}{2(3) {}^{2} } = k](https://tex.z-dn.net/?f=%20%5Cfrac%7B200%7D%7B2%283%29%20%7B%7D%5E%7B2%7D%20%7D%20%20%3D%20k)
![\frac{200}{18} = k](https://tex.z-dn.net/?f=%20%5Cfrac%7B200%7D%7B18%7D%20%20%3D%20k)
![\frac{100}{9} = k](https://tex.z-dn.net/?f=%20%5Cfrac%7B100%7D%7B9%7D%20%20%3D%20k)
Now, since we know our constant, let find p.
![\frac{p}{q {r}^{2} } = \frac{100}{9}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bp%7D%7Bq%20%7Br%7D%5E%7B2%7D%20%7D%20%20%3D%20%20%5Cfrac%7B100%7D%7B9%7D%20)
Q is 5, and r is 2.
![\frac{p}{5( {2}^{2}) } = \frac{100}{9}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bp%7D%7B5%28%20%7B2%7D%5E%7B2%7D%29%20%7D%20%20%3D%20%20%5Cfrac%7B100%7D%7B9%7D%20)
![\frac{p}{20} = \frac{100}{9}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bp%7D%7B20%7D%20%20%3D%20%20%5Cfrac%7B100%7D%7B9%7D%20)
![p = \frac{2000}{9}](https://tex.z-dn.net/?f=p%20%3D%20%20%5Cfrac%7B2000%7D%7B9%7D%20)
Answer:
c = 53 yd is the answer.
Step-by-step explanation:
a = 45 yd
b = 28 yd
c = ?
According to the Pythagorean Theorem,
a² + b² = c²
45² + 28² = c²
2025 + 784 = c²
c² = 2809
c = 53 yd
∴ The dog runs 53 yd
(a) The rate that the point 8,28 represents is 3.5 cm/s since 28/8 = 3.5
(b) The unit rate is 3.5 cm/s since the rate is constant.
(c) The two points lie on the same line and that both points results to a rate of 3.5 cm/s.<span />
Actually Welcome to the Concept of the Angles,.
Since,the AE is a angle bisector, hence, BAE = EAC simply.
hence we equate them..
===> x+ 30 = 3x - 10
==> 3x - x = 30 + 10
==> 2x = 40
==> x = 20°
hence the major angle EAC = 3(20)-10 = 60-10 = 50°
hence, angle EAC = 50°