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3 years ago

Draw a rectangle with the vertices A (2, 1) B (4, 1) C (4, 4) and D (2, 4)

Mathematics

1 answer:

Rufina [12.5K]3 years ago

3 0

The point was reflected over the y -axis and translated up 4 units.

The point was translated left 10 units and up 4 units.

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3. (-2,-2)

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B' = (4,-7)

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There are many cylinders with a height of 9 inches. Let r represent the radius in

mylen [45]

Answer:

Step-by-step explanation:

V, r, h are the volume, radius, and height, respectively.

V = πr²h = 9πr²

The only error in your previous answers was that you forgot the π.

if r = 1, V = 9π1² = 9π ≅ 28 in³

if r = 2, V = 9π2² = 36π ≅ 113 in³

if r = 3, V = 9π3² = 81π ≅ 254 in³

8 0

3 years ago

25/9 converted into a mixed number equals

blagie [28]

First figure out how many times 9 can go into 25 **do the highest amount of times it can go in-
<span><span>9x1=9 </span><span>9x2=18 </span><span>9x3=27 </span><span>9x4=<span>36
nine can go in 2 times because 3 times would be way to much
so you're mixed number would be 2
now to figure out you're numerator do 25-18=7
Now it would be 2 7/25
so you're mixed number,then the numerator,finally denomantor ALWAYS stays the same.
*IF YOU'RE NUMERATOR AND DENOMANTOR CAN BE REDUCED THEN REDUCE</span></span></span>

6 0

4 years ago

Jason’s credit card has an apr of 17.02% and a 30-day billling cycle. the following table details jason’s transactions with that

forsale [732]

The method of computing that would result in a greater finance charge is a. the daily balance method will have a finance charge $1.02 greater than the adjusted balance method.

<h3>What is the Adjusted Balance Method?</h3>

This refers to the method of accounting that makes use of the owed amount of money at the end of a billing cycle to make its computation on an account after the credits are calculated.

Hence, we can see that when comparing the adjusted balance method to the daily balance method that calculates the interest charges at the end of the day, the daily balance method would have a higher finance charge.

Read more about adjusted balance methods here:

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5 0

2 years ago

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$