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Afina-wow [57]
3 years ago
7

Draw a rectangle with the vertices A (2, 1) B (4, 1) C (4, 4) and D (2, 4)

Mathematics
1 answer:
Rufina [12.5K]3 years ago
3 0

The point was reflected over the y -axis and translated up 4 units.

The point was translated left 10 units and up 4 units.

_________________________________________________________

3. (-2,-2)

_________________________________________________________

B' = (4,-7)

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lutik1710 [3]
The total square footage 2,070 Sq Ft
8 0
3 years ago
If the sum of the first 12 terms of a geometric series is 8190 and the common ratio is 2. Find the first term and the 20th term.
Reil [10]

The first term is 2 and the 20th term is 1048576 .

<u>Step-by-step explanation:</u>

Here we have , If the sum of the first 12 terms of a geometric series is 8190 and the common ratio is 2. We need to Find the first term and the 20th term. Let's find out:

We know that Sum of a GP is :

⇒ S_n = \frac{a(r^n-1)}{r-1}

So ,Sum of first 12 terms is :

⇒ S_1_2 = \frac{a(2^{12}-1)}{2-1}

⇒ 8190=a(2^{12}-1)

⇒ \frac{8190}{4095}=a

⇒ a=2

Now , nth term of a GP is

⇒ a_n = ar^{n-1}

So , 20th term is :

⇒ a_2_0 = 2(2)^{20-1}

⇒ a_2_0 = (2)^{20}

⇒ a_2_0 = 1048576

Therefore , the first term is 2 and the 20th term is 1048576 .

8 0
4 years ago
True or false? in order to inscribe a circle in a triangle, the circle's center must be placed at the circumcenter of the triang
Dvinal [7]

Answer:

<h2>False.</h2>

Step-by-step explanation:

A inscribe circle in a triangle means to draw the biggest circle possible inside such triangle. To do that perfectly, we first have to find the incenter of the circle, which is the intersection of all three internal bisector of the triangle, that point is the center of the inscribed circle.

Therefore, the statement is false.

In addition, a circumcenter allow to perfectly draw a circumscribed circle, which is outside the triangle, which is not the case here.

An image showing the inscribed circle is attached.

6 0
3 years ago
For each of the following state the condition that supports why quadrilateral WXYZ is a pallelogram.
Veronika [31]

  • 1.}--diagonals bisect each other
  • 2...and...3}.---two pairs of opposite sides are parallel and equal
  • 4.}--opposite angles are equal
  • 5…}---diagonals bisect each other

  • <em><u>none. I has no solutions (in all x, y and z) because in case x+y+z is 3 it can never be 4. So, it's imposible to find any (x,y,z) so that they satisfy both equations.</u></em>
  • <em><u>To find the slope, convert the equation 21x - 3y + 18 = 0 to slope-intercept form (y = mx + b, where m is the slope and b is the y-intercept). To do so, first subtract 18 and 21x from both sides to get -3y = -21x - 18. Then divide both sides by -3 to get y = 7x + 6. Therefore the slope is 7.</u></em>

<em><u> </u></em><em><u>if my answer is wrong, report</u></em><em><u> </u></em><em><u>i</u></em><em><u>TS </u></em><em><u>ok </u></em>

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2 years ago
1,1,2,3,5,6,7,8,8,8,9,14
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2 because you know what you mean about the following problems
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