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3 years ago

12

What would the resulting cross section be if the sphere were intersected horizontally by the plane?

1 answer:

Inessa [10]3 years ago

4 0

Answer:

GOD IS SO AMAZING, GOS BLESS U AND UR FAMILY

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Knowing 6x-y above 4y=2,calculate x and y.

bagirrra123 [75]

Answer:

x= 0.083 y = 0.5

Step-by-step explanation:

step 1:

equation 1: 6x -y

equation 2 : 4y = 2

from equation (2) 4y = 2, we calculate value of y to get x

4y = 2 ... divide both sides by 4

<u>4y </u>= <u>2</u>

4 4 y = 1 /2. y = 0.5

Step 2:

input the value of y into the equation 1 to get x.

6x - y = 0

6x - 0.5 = 0

6x- 0.5 + 0.5 = 0 + 0.5 ( Add both sides of the equation by 0.5)

6x = 0.5.... divide both sides of the term by 6

<u>6x </u>= 0.5

6 6

x = 0.083

therefore, y = 0.5 and x = 0.0833

6 0

2 years ago

3x + 6 = y<br><br> solve for x

tekilochka [14]

Answer:

x=1/3y - 2

Step-by-step explanation:

8 0

3 years ago

If t a n squared θ = 3 /8 , what is the value of s e c θ

TEA [102]

We can use 3 facts:

$\tan{\theta}=\frac{y}{x}$

$\sec{\theta}=\frac{r}{x}$

$x^2+y^2=r^2$

So, to find our x and our y we can do:

$\tan^2{\theta}=\frac{3}{8} \implies \\ \tan{\theta}=\pm{\sqrt{\frac{3}{8}}=\pm\frac{\sqrt{3}}{\sqrt{8}}$ So, now that we know our x and our y we can find our r.

$(\sqrt{3})^2+(\sqrt{8})^2=11 \implies r=\sqrt{11}$

You'll notice, though, that there were two solutions for $\tan{\theta}$ , which means we have a positive and a negative for our x. So:

$\sec{\theta}=\frac{\sqrt{11}}{\sqrt{8}} \\ \sec{\theta}=-\frac{\sqrt{11}}{\sqrt{8}}}\\ \text{Rationalizing both of them:}\\ \sec{\theta}=\frac{\sqrt{88}}{8} \\ \sec{\theta}=-\frac{\sqrt{88}}{8}$

7 0

3 years ago

Read 2 more answers

39 points!!! answer all questions

Lina20 [59]

Step-by-step explanation:

<h3>a. </h3>

$= {2}^{x}$

$= {2}^{3}$

$= 2 \times 2 \times 2$

$= 8$

<h2>______________</h2>

<h3>B. </h3>

$= {x}^{2}$

$= {3}^{2}$

$= 3 \times 3$

$= 9$

<h2>______________</h2>

<h3>C. </h3>

$= {1}^{x}$

$= {1}^{3}$

$= 1 \times 1 \times 1$

$= 1$

<h2>______________</h2>

<h3>D. </h3>

$= {x}^{1}$

$= {3}^{1}$

$= 3$

<h2>______________</h2>

<h3>E. </h3>

$= {( \frac{1}{2}) }^{x}$

$= {( \frac{1}{2}) }^{3}$

$= \frac{ {1}^{3} }{ {2}^{3} }$

$= \frac{1}{8}$

8 0

3 years ago

Please help me... Question is in the picture

zmey [24]

The answer is “122“ 180-58 = 122

5 0

3 years ago