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3 years ago

Which ordered pair is a solution of the equation? Y= 32x+5

Mathematics

1 answer:

Natasha_Volkova [10]3 years ago

4 0

Step-by-step explanation:

where are the ordered pairs?

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7/20 write the decimal from of each rational number and determine

NikAS [45]

Answer:

0.35

Step-by-step explanation:

Step 1:

7/20 = 35/100

Step 2:

35 ÷ 100

Answer:

0.35

Hope This Helps :)

7 0

3 years ago

Can someone just help me!

masya89 [10]

Answer: C

Step-by-step explanation: use calculator soup, you can do anything with fractions

5 0

3 years ago

Differentiate the following by using "limit"

Nat2105 [25]

Answer:

$\rm \displaystyle \frac{d }{dx} \sqrt{x} = \frac{ 1 }{ 2\sqrt{x } }$

Step-by-step explanation:

we want to differentiate the following by using limit:

$\displaystyle \frac{d}{dx} \sqrt{x}$

derivative definition by limit given by

$\rm \displaystyle \frac{d}{dx} = \lim _{\Delta x \to 0} \left( \frac{f(x + \Delta x) - f(x)}{ \Delta x} \right)$

given that,

f(x)=√x

so,

f(x+∆x)=√(x+∆x)

thus substitute:

$\rm \displaystyle \frac{d }{dx} \sqrt{x} = \lim _{\Delta x \to 0} \left( \frac{ \sqrt{x + \Delta x}- \sqrt{x} }{ \Delta x} \right)$

multiply both the numerator and denominator by the conjugate of the numerator:

$\rm \displaystyle \frac{d }{dx} \sqrt{x} = \lim _{\Delta x \to 0} \left( \frac{ \sqrt{x + \Delta x}- \sqrt{x} }{ \Delta x} \times \frac{ \sqrt{x + \Delta x} + \sqrt{x} }{\sqrt{x + \Delta x} + \sqrt{x}} \right)$

simplify which yields:

$\rm \displaystyle \frac{d }{dx} \sqrt{x} = \lim _{\Delta x \to 0} \left( \frac{ (\sqrt{x + \Delta x}) ^{2} - x }{ \Delta x(\sqrt{x + \Delta x} + \sqrt{x})} \right)$

simplify square:

$\rm \displaystyle \frac{d }{dx} \sqrt{x} = \lim _{ \Delta x \to 0} \left( \frac{ x + \Delta x - x }{ \Delta x(\sqrt{x + \Delta x} + \sqrt{x})} \right)$

collect like terms:

$\rm \displaystyle \frac{d }{dx} \sqrt{x} = \lim _{\Delta x \to 0} \left( \frac{ \Delta x }{ \Delta x(\sqrt{x + \Delta x} + \sqrt{x})} \right)$

reduce fraction:

$\rm \displaystyle \frac{d }{dx} \sqrt{x} = \lim _{\Delta x \to 0} \left( \frac{ 1 }{ (\sqrt{x + \Delta x} + \sqrt{x})} \right)$

get rid of ∆x as we are approaching its to 0

$\rm \displaystyle \frac{d }{dx} \sqrt{x} = \frac{ 1 }{ \sqrt{x } + \sqrt{x}}$

simplify addition:

$\rm \displaystyle \frac{d }{dx} \sqrt{x} = \frac{ 1 }{ 2\sqrt{x } }$

and we are done!

7 0

3 years ago

What is the area of a parallelogram with a base of 13.5 in. and a height of 12.2 in.?

yulyashka [42]

<h3>Answer: 164.7 square inches</h3>

============================================

Explanation:

The area of a parallelogram is equal to the base times height

area = base*height

area = 13.5*12.2

area = 164.7

This is pretty much identical to a rectangle's area formula. This is because a rectangle is a special type of parallelogram (one with all four angles at 90 degrees).

8 0

3 years ago

Read 2 more answers

Please help me s+5s=

AfilCa [17]

Answer:

s+5s=6s

Step-by-step explanation:

not sure if im right but hope this helps

4 0

3 years ago

Read 2 more answers