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2 years ago

Please help me solve this

Mathematics

1 answer:

alexandr1967 [171]2 years ago

3 0

Answer:

20.5

Step-by-step explanation:

By the Triangle Midsegment Theorem, the midsegment connecting the midpoints of two sides of a triangle is parallel to the third side of the triangle, and the length of this midsegment is half the length of the third side. Therefore, (1/2)FH ≡ IH, (1/2)HG ≡ HJ. Knowing that IJ = 8 gives you the presidence to solve for the perimeter.

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If a triangle has one obtuse angle, then it is an obtuse triangle.

nalin [4]

No the sum of measures would exceed 180, therefore it would not be a obtuse triangle

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3 years ago

During a sale, a dress is marked down from a selling price of $68 to a sale price of $44.20 What is the percent markdown?

ipn [44]

44.20 is 40% of 68.00 if 34.00 is 50%

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3 years ago

a large water tank measures 6 feet across and 4 feet high. it is being filled with water at a rate of 10 gallons per minute. abo

Ray Of Light [21]

Answer:

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Step-by-step explanation:

oooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooh

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3 years ago

Value of the derivative of g(x)=8-10Cosx at 'x=0' is?

VLD [36.1K]

Answer:

g'(0) = 0

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Function Notation

Pre-Calculus

Unit Circle

Calculus

Derivatives
Derivative Notation
The derivative of a constant is equal to 0
Derivative Property: $\frac{d}{dx} [cf(x)] = c \cdot f'(x)$
Trig Derivative: $\frac{d}{dx} [cos(x)] = -sin(x)$

Step-by-step explanation:

Step 1: Define

g(x) = 8 - 10cos(x)

x = 0

Step 2: Differentiate

Differentiate [Trig]: g'(x) = 0 - 10[-sin(x)]
Simplify Derivative: g'(x) = 10sin(x)

Step 3: Evaluate

Substitute in x: g'(0) = 10sin(0)
Evaluate Trig: g'(0) = 10(0)
Multiply: g'(0) = 0

3 0

3 years ago

The density of a certain material is such that it weighs 71 pounds for every 2.5 gallons of volume. Express this density in tons

kvasek [131]

Answer:

$d=3.75\ \text{tons per cubic meter}$

Step-by-step explanation:

Given that,

Mass of a certain material, m = 71 pounds

Since, 1 ton = 2000 pounds

71 pounds = 0.0355 ton

Volume of the material, V = 2.5 gallons

Since, 1 m³ = 264.172 gallon

2.5 gallon = (2.5/264.172 ) m³

Density,

$d=\dfrac{m}{V}\\\\d=\dfrac{0.0355\ \text{tons}}{\dfrac{2.5}{264.172}\ m^3}\\\\d=3.75\ \text{tons per cubic meter}$

5 0

2 years ago