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xenn [34]
3 years ago
9

HELP pleasee and ty to whoever does!!

Mathematics
1 answer:
Margaret [11]3 years ago
6 0
Answers:
26) 50 percent chance
27) 25 percent chance
28) About 25 times
29) About 20 times
You might be interested in
use the elimination method to solve the system of equations. choose the correct ordered pair. 6x-4y=-8 and 11x+4y=76​
nika2105 [10]

Answer:

(4,8)

Step-by-step explanation:

6x-4y=-8

11x+4y=76  eliminate y

6x+11y=-8+76

17 x=68

x=68/17=4

substitute x :

6x-4y=-8

6(4)-4y=-8

-4y=-8-24

y=-32/-4

y=8

4 0
4 years ago
Please help me fasttttttttt
prohojiy [21]
X = 60 degrees
Y = 60 degrees
Z = 40 degrees
6 0
3 years ago
¿Cuál de las siguientes funciones es una función constante? a. Y=x+1 b. Y=x+2 c. X=y+3 d. Y=3
goldenfox [79]

Answer:

Option D y=3

Step-by-step explanation:

The question in English is

Which of the following functions is a constant function?

we know that

A <u>constant function</u> is a function whose output value is the same for every input value

so

<u><em>Verify each case</em></u>

case A) y=x+1

This is not a constant function, this is a linear equation

Is a function whose output value is different for every input value

case B) y=x+2

This is not a constant function, this is a linear equation

Is a function whose output value is different for every input value

case C) x=y+3

This is not a constant function, this is a linear equation

Is a function whose output value is different for every input value

case D) y=3

This is a constant function

Is a function whose output value is the same for every input value

3 0
3 years ago
The lengths of pregnancies are normally distributed with a mean of 266 days and a standard deviation of 15 days.
inessss [21]

The lengths of pregnancies are normally distributed with a mean of 266 days and a standard deviation of 15 days.

That is,

Consider X be the length of the pregnancy

Mean and standard deviation of the length of the pregnancy.

Mean \mu =266\\

Standard deviation \sigma =15

For part (a) , to find the probability of a pregnancy lasting 308 days or longer:

That is, to find P(X\geq 308)

Using normal distribution,

z=\frac{X-\mu}{\sigma}

z=\frac{308-266}{15}

=\frac{42}{15}

Thus z=2.8

So P\left (X\geq 308  \right )=1-P(X

=1-P(z

=1-Table\:  value\:  of\:  2.8

=1-0.99744

=0.00256

Thus the probability of a pregnancy lasting 308 days or longer is given by 0.00256.

This the answer for part(a): 0.00256

For part(b), to find the length that separates premature babies from those who are not premature.

Given that the length of pregnancy is in the lowest 3​%.

The z-value for the lowest of 3% is -1.8808

Then X=\frac{X-\mu}{\sigma}\Rightarrow X=z*\sigma+\mu

This implies X=-1.8808*15+266=237.788

Thus the babies who are born on or before 238 days are considered to be premature.

5 0
3 years ago
Emma made 2/3 of a litre of lemonade. she split them into cups with 1/6 of a litre in each. How many cups did she have
eimsori [14]
Lemonade made= 2(l)/3=2/3 of a litre
qty in each cup=1(l)/6=1/6 of a litre
no of cup=2l/3÷1(l)/6
   ⇒2l/3×6/1(l)
⇒4
6 0
3 years ago
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