HELP pleasee and ty to whoever does!!
1 answer:
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Answer:
Step-by-step explanation:
in this case we have a right angled triangle, whenever you see this triangle think of the TRIG RATIOS * sin, cos & tan* but if it was another triangle besides right angled triangle you use SINE RULE OR COSINE RULE
SOLUTION
Answer:
mid point of AB (0.5 , 0)
Step-by-step explanation:
2x + 5y = 1 2x = 1 - 5y
y = 2xy+ 5 = (1 - 5y)*y + 5 = y - 5y² + 5
y-y = y - 5y² + 5 - y = - 5y² + 5
0 = - 5y² + 5
5y² = 5
y² = 1
y = 1 or y = -1
if y = 1 x = 1/2 (1 - 5) = -2 .... point A (-2 , 1)
if y = -1 x = 1/2 (1 + 5) = 3 ..... point B (3 , -1)
mid point of AB (x' , y') : x' = 1/2 (x₁ + x₂) = 1/2 (-2 + 3) = 1/2
y' = 1/2 (y₁ + y₂) = 1/2 (-1 + 1) = 0
