Question

Convergence in mathematics ​

Answer 1

Answer:

Converges to $\frac{\sqrt{\pi }}{2}$

Step-by-step explanation:

$\int _0^{\infty \:}e^{-x^2}dx$ = $\lim_{b \to \infty}$ $\int _0^{b \:}e^{-x^2}dx$ =  $\frac{\sqrt{\pi }}{2}$

steps:

write improper integral as a limit

solve integral

apply limit

If limit exists and this number is finite, the improper integral converges

Answer 2

Answer:

that looks so complicated im dropping out

Step-by-step explanation: