Answer:
25
Step-by-step explanation:
that what i got
Answer:
i) Probability that both candidates employed are women = 5/14
ii) Probability that the second candidate is a woman = 5/8
iii) Probability that the first candidate is a woman given that second one is a woman = 4/5
Step-by-step explanation:
Let the probability that a man is employed be P(M) = 3/8
Probability that a woman is employed P(W) = 5/8
a) Probability that both candidates employed are women = (5/8) × (4/7) = 5/14
b) Probability that the second candidate is a woman = (probability that first candidate is a man and second candidate is a woman) + (probability that first candidate is a woman & second candidate is a woman)
= (3/8)(5/7) + (5/8)(4/7) = (15/56) + (20/56) = 35/56 = 5/8
c) Probability that the first candidate is a woman given that second one is a woman
Given that the second candidate was a women, means that the first candidate-women was selected among other four women.
Probability = (4/8)/(5/8) = 4/5
Answer:
C
Step-by-step explanation:
The solution triangle is attached below :
Tonobtinnthe Angle formed, θ; we apply trigonometry ;
Using ;
Cos θ = Adjacent / hypotenus
Cos θ = 4 / 7
θ = Cos^-1(4/7)
θ = 55.15°
θ = 55°
Answer:
The answer is a trapezoid.
Answer:
1100 field-side tickets and 4500 end-zone tickets.
Step-by-step explanation:
Let x represent number of field side tickets and y represent number of end-zone tickets.
We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:

We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.
Cost of x field side tickets would be
and cost of y end-zone tickets would be
.
The total amount of money received for the tickets was $134000. We can represent this information in an equation as:

Upon substituting equation (1) in equation (2), we will get:







Therefore, 1100 field side tickets were sold.
Upon substituting
in equation (1), we will get:


Therefore, 4500 end-zone tickets were sold.