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vampirchik [111]
3 years ago
12

there are 18 black socks and 12 Navy socks in your drawer the room is dark and you cannot turn on the light what is the least nu

mber of socks that you have to take out of the drawer to be certain that you have a pair of the same color
Mathematics
2 answers:
Yakvenalex [24]3 years ago
8 0

Answer:

Step-by-step explanation:

Natasha_Volkova [10]3 years ago
4 0

Answer:

3/5

Step-by-step explanation:

To have the best chance of pulling a pair with the same color you should try to get a pair of black socks. There is a 3/5 chance of pulling a black sock so this means for every 5 socks you pull you get 3 black socks or 2 navy socks. Either way you will get a pair of socks with the same color. (Double check to make sure I'm correct)

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What is the cross section shown below?
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<h3>Answer: Choice A) circle</h3>

Explanation:

Imagine that white rectangle as a blade that cuts the cylinder as the diagram shows. If you pull the top cylinder off and examine the bottom of that upper piece, then you'll see a circle forms. It's congruent to the circular face of the original cylinder. This is because the cutting plane is parallel to both base faces of the cylinder. Any sort of tilt will make an ellipse form. Keep in mind that any circle is an ellipse, but not vice versa.

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What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.
Paul [167]

Answer:

1.60 ft^{2}

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = \pir^{2}

So that,

for the inner part of the pipe,

r = \frac{diameter}{2}

 = \frac{5}{2}

 = 2.5 feet

Area of the inner part of the pipe = \pir^{2}

                                 = 3.14 x (2.5)^{2}

                                 = 19.625

Are of the inner part of the pipe is 19.63 ft^{2}.

Total diameter of the pipe = 5 + 0.2

                                           = 5.2 feet

r = \frac{5.2}{2}

 = 2.6 feet

Area of the pipe = \pir^{2}

                            = 3.14 x (2.6)^{2}

                            = 21.2264

Area of the pipe is 21.23 ft^{2}.

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

                                           = 21.2264 - 19.625

                                           = 1.6014

The cross sectional area of the cement pipe is 1.60 ft^{2}.

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2 years ago
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