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3 years ago

14

When stacys son Kevin solves the problem

1 answer:

LUCKY_DIMON [66]3 years ago

6 0

Answer:

,,,,,,,,,,,,,,mmmmmmmm

Step-by-step explanation:

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What is the slope of the line through (-9,-6) and (3,-9)?

tatuchka [14]

Answer:

slope = - $\frac{1}{4}$

Step-by-step explanation:

Calculate the slope m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (- 9, - 6) and (x₂, y₂ ) = (3, - 9)

m = $\frac{-9+6}{3+9}$ = $\frac{-3}{12}$ = - $\frac{1}{4}$

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4 years ago

Which are the solutions of the quadratic equation? x2 = –5x – 3

Svetradugi [14.3K]

$x^2=-5x-3\\x^2+5x+3=0\\\\a=1;\ b=5;\ c=3\\\Delta=b^2-4ac\\\\\Delta=5^2-4\cdot1\cdot3=25-12=13 \ \textgreater \ 0\\\\then\\x_1=\dfrac{-b-\sqer\Delta}{2a}\ and\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\x_1=\dfrac{-5-\sqrt{13}}{2\cdot1}=\boxed{\dfrac{-5-\sqrt{13}}{2}}\\\\x_2=\dfrac{-5+\sqrt{13}}{2\cdot1}=\boxed{\dfrac{-5+\sqrt{13}}{2}}$

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3 years ago

drag equations to each row to show why the equation of a straight line is why equals 3X, where three is the slope

DiKsa [7]

Answer:

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Step-by-step explanation:

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4 years ago

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nalin [4]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Families USA, a monthly magazine that discusses issues related to health and health costs, surveyed 20 of its subscribers. It fo

Harman [31]

Answer:

(a) The 90 percent confidence interval for the population mean yearly premium is ($10,974.53, $10983.47).

(b) The sample size required is 107.

Step-by-step explanation:

(a)

The (1 - <em>α</em>)% confidence interval for population mean is:

$CI=\bar x\pm t_{\alpha/2, (n-1)}\times \frac{s}{\sqrt{n}}$

Given:

$\bar x=\$10,979\\s=\$1000\\n=20$

Compute the critical value of <em>t</em> for 90% confidence level as follows:

$t_{\alpha/2, (n-1)}=t_{0.10/2, (20-1)}=t_{0.05, 19}=1.729$

*Use a <em>t-</em>table.

Compute the 90% confidence interval for population mean as follows:

$CI=\bar x\pm t_{\alpha/2, (n-1)}\times \frac{s}{\sqrt{n}}$

$=10979\pm 1.729\times \frac{1000}{\sqrt{20}}\\=10979\pm4.47\\ =(10974.53, 10983.47)$

Thus, the 90 percent confidence interval for the population mean yearly premium is ($10,974.53, $10983.47).

(b)

The margin of error is provided as:

MOE = $250

The confidence level is, 99%.

The critical value of <em>z</em> for 99% confidence level is:

$z_{\alpha/2}=z_{0.01/2}=z_{0.005}=2.58$

Compute the sample size as follows:

$MOE= z_{\alpha/2}\times \frac{s}{\sqrt{n}}$

$n=[\frac{z_{\alpha/2}\times s}{MOE} ]^{2}$

$=[\frac{2.58\times 1000}{250}]^{2}$

$=106.5024\\\approx107$

Thus, the sample size required is 107.

4 0

3 years ago