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3 years ago

Please help (There is a word bank at the bottom of each screenshot)

Biology

1 answer:

natali 33 [55]3 years ago

6 0

Answer:

First slide

Plant - Producer

Bugs and Lizard - Primary

Snake, Scorpion, Tarantula - Secondary

Hawk and Fox - Tertiary

Second Slide

Plant - Producer

Moose, Elk, Insect, Bird, Mouse - Primary

Bird, Owl, Weasel - Secondary

Wolf, Bobcat - Tertiary

Third Slide

Plant - Producer

Deer, Rodent, Bird, Insects - Primary

Fox, Owl, Skunk, Bird, Opossum - Secondary

Bear, Cougar - Tertiary

Fourth Slide

Deer, Elk, Fish, Insect, Small Mammals - Primary

Owl, Weasel, Raccoon, Frog, Woodpecker - Secondary

Cougar, Bear, Lynx, Wolf - Tertiary

Okay, I tried but I'm not sure if the tertiaries and quaternaries are correct. Is the choices below used once? I don't think any one of the animals would be the top predators here so I chose most of them as a tertiary. If not correct then it's quaternary. Sorry!

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Sickle-cell anaemia is an autosomal recessive genetic disorder. Individuals with the homozygous recessive have sickle-shaped blood cells. Whereas, individuals with heterozygous are only carrier of sickle cell trait. The carrier individuals are resistant to malarial parasite and do not have malaria.

As per the question, 4% of an African population is born with sickle-cell disease, then the percentage of the population is heterozygous and resistant to malaria will be:

Hardy-Weinberg formula is equilibrium,

p² + 2pq + q² = 1

p = frequency of the dominant allele in the population

q = frequency of the recessive allele in the population

p2 = percentage of homozygous dominant individuals

q2 = percentage of homozygous recessive individuals

2pq = percentage of heterozygous individuals

Given, homozygous recessive for this gene (q2) is 4% which is 0.04, the square root (q) is 0.2 (20%) then p should be 1-0.2 = 0.8 (20%).

Thus, the frequency of heterozygous individuals = 2pq.

2 (0.8 x 0.2) = 0.32 (32%).

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