All categories

3 years ago

What makes an endospore so resistant?

Biology

1 answer:

ziro4ka [17]3 years ago

3 0

Answer:

the answer is a.presence of high metabolic rate

You might be interested in

What is the main difference between weather and climate? A. Weather refers to temperature and precipitation, whereas climate ref

Nuetrik [128]

D. Weather refers to short-term conditions, whereas climate refers to long-term conditions. hope this helps!

8 0

3 years ago

Please help! I’m so stuck in bio...

Helen [10]

Answer:

3,5,6,4,1,2

Explanation:

3.interphase is the first phase of the cell cycle and the longest where the cell grows and prepares for mitosis through dna replication

5.chromosomes form in the first phase of mitosis, prophase

6.chromosomes line up along the equator during the second phase of mitosis, metaphase

4 sister chromatids separate during anaphase

1 two new nuclei form during telphase

2 cytokinesis is the separation of cytoplasm , resulting in two daughter cells

8 0

3 years ago

What device transforms electrical energy into mechanical energy? a. an electromagnet b. an electric motor c. a generator d. an e

alina1380 [7]

Electric motors transform electrical energy into mechanical energy so the answer would be B.

Explanation:

7 0

3 years ago

Around 40% of cats with white fur and blue eyes are deaf. The gene responsible is pleiotropic. What does this mean?

Vesna [10]

The gene is responsible for the cat's hearing.

4 0

3 years ago

Suppose the human trait for hair type is controlled by a simple dominant and recessive relationship at one locus. Curly hair, C,

myrzilka [38]

Answer:

A) The frequency of the dominant allele, C $= 0.4376$

B) frequency of the heterozygous genotype, Cc $= 0.2461$

Explanation:

Given -

Curly hair, C, is the dominant allele, and straight hair, c, is the recessive allele

Number of students with curly hair is $37$

Thus frequency of genotype "CC"

$= q^{2} = \frac{37}{117} \\= 0.3162$

Thus, frequency of allele "q"

$= \sqrt{0.3162} \\= 0.5623$

As per Hardy Weinberg's first equation-

$p+q=1$

Substituting the value of q, we get -

$p+0.5623=1\\p= 0.4376$

As per Hardy Weinberg's second equation -

$p^2+q^2+2pq=1\\$

Substituting the values of "p" and "q" we get -

$0.4376^{2} + 0.3162+2pq = 1\\2pq = 0.2461\\$

Hence,

A) The frequency of the dominant allele, C $= 0.4376$

B) frequency of the heterozygous genotype, Cc $= 0.2461$

8 0

3 years ago

Read 2 more answers