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Tcecarenko [31]
2 years ago
6

Define a class named Money that stores a monetary amount. The class should have two private integer variables, one to store the

number of dollars and another to store the number of cents. Add accessor and mutator functions to read and set both member variables. Add another function that returns the monetary amount as a double. Write a program that tests all of your functions with at least two different Money objects.
Computers and Technology
1 answer:
WINSTONCH [101]2 years ago
6 0

Answer:

#include<iostream>

using namespace std;

class Money{

    private:

        int dollars;  

       int cents;

   public:

       Money(int d=0, int c=0){

          setDollar(d);

          setCent(c);

       }

       void setDollar(int d){

           dollars = d;

       }

       void setCent(int c){

           cents = c

       }

       int getDollar() {

           return dollars;

       }

       int getCent() {

           return cents;

       }

       double getMoney(){

          return (dollars + (cents/100));

       }

};

// testing the program.

int main(){

  Money Acc1(3,50);

  cout << M.getMoney() << endl;

  Money Acc2;

  Acc2.setDollars(20);

  Acc2.setCents(30);

  cout <<"$" << Acc2.getDollars() << "." << Acc2.getCents() << endl;

  return 0;

}

Explanation:

The C++ source code defines the Money class and its methods, the class is used in the main function as a test to create the instances of the money class Acc1 and Acc2.

The object Acc2 is mutated and displayed with the "setDollar and setCent" and "getDollar and getCent" methods respectively.

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A painting company has determined that for every 115 square feet or wall space, one gallon of paint and eight hours of labor wil
Kay [80]

The program to calculate the total paint cost and other values is given below.

#include <iostream>

using namespace std;

int main() {  

 int rooms, laborChrg = 18;

 float paintChrg;

 float feetPerRoom[rooms];  

 float paintReq, laborHrs, paintCost, laborCost, totalCost, totalsqft=0;  

 cout<<"Enter the number of rooms to be painted "<<endl;

 cin>>rooms;  

 for(int i=0; i <= rooms; i++)

 {

 cout<<"Enter the square feet in room "<<endl;

 cin>>feetPerRoom[i];  

 // shortcut operator which is equivalent to totalsqft = totalsqft +     feetPerRoom[i];

 totalsqft += feetPerRoom[i];

 }  

 cout<<"Enter the cost of the paint per gallon "<<endl;

 cin>>paintChrg;  

 laborHrs = (totalsqft/115)*8;

 laborCost = laborHrs * laborChrg;  

 paintReq = totalsqft/115;

 paintCost = paintReq * paintChrg;  

 totalCost = laborCost + paintCost;  

 cout<<"The number of gallons of paint required "<<paintReq<<endl;

 cout<<"The hours of labor required "<<laborHrs<<endl;

 cout<<"The cost of the paint is "<<paintCost<<endl;

 cout<<"The labor charges are "<<laborHrs<<endl;

 cout<<"The Total cost of the paint job is "<<totalCost<<endl;  

 return 0;

}

Explanation:

The header files for input and output are imported.

#include <iostream>

using namespace std;

All the variables are taken as float except labour charge per hour and number of rooms.

The user is asked to input the number of rooms to be painted. An array holds the square feet in each room to be painted.

cout<<"Enter the number of rooms to be painted "<<endl;

cin>>rooms;  

for(int i=0; i <= rooms; i++)

{

cout<<"Enter the square feet in room "<<endl;

cin>>feetPerRoom[i];  

totalsqft += feetPerRoom[i];

}  

The above code asks for square feet in each room and calculates the total square feet to be painted simultaneously.

All the data to be displayed is calculated based on the values of labor charge per hour and gallons of paint needed, given in the question.

laborHrs = (totalsqft/115)*8;

laborCost = laborHrs * laborChrg;

paintReq = totalsqft/115;

paintCost = paintReq * paintChrg;

totalCost = laborCost + paintCost;

All the calculated values are displayed in the mentioned order.

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Explanation:

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The following code does not work as intended. It is meant to input two test grades and return the average in decimal format:
vredina [299]

Answer:

Type casting error

Explanation:

Logically, the program is correct and it is expected to return the average value. However, test1 and test2 are int values and when you applies any algebraic expression on Int, it will result into Int.

So, in this part (test1 + test2 )/2, two integers are adding and the final result is still an integer and this part will act as an integer even if you multiple or divide with any external number.

For example,

test1 = 4

test2 = 5

test1 + test2 = 9

Now, if you divide it by 2, it will still react as an integer portion. So, 9/2 would result in 4 instead of 4.5. All the calculation is done on the right side before assigning it to a double variable. Therefore, the double variable is still getting the int value and your program is not working correctly.

The solution is to typecast the "(test1 + test2 )/2" portion to double using Double.valueOf(test1 + test2)/2 ;

I have also attached the working code below.

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

 System.out.println("Hello World");

 Scanner scan = new Scanner (System.in);

 int test1 = scan.nextInt();

       int test2 = scan.nextInt();

       double average = Double.valueOf(test1 + test2)/2 ;

       System.out.println("Answer: " + average);

}

}

4 0
3 years ago
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