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mafiozo [28]
3 years ago
10

Scientists collected samples of each group of flies. They placed some of the flies, together, in flasks with both apples and haw

thorn
fruit. Other flasks contained either apple-eating flies or hawthorne-eating flies. Only the flies in the single fruit flasks mated and
produced offspring. To confirm their results, the scientists isolated flies from each group and put one of each into a flask with food.
Eventually the flies died
without mating. What conclusions apply to this situation? All BUT ONE could apply.
A)One fly species became two species via natural selection.
B)By eating different fruits, the flies changed genetically.
C)Over time, each group evolved different traits that aided in their survival.
D)Living in the ground and emerging a different times was a kind of
geographic isolation
Biology
1 answer:
Elina [12.6K]3 years ago
7 0

Answer:

D, Gene flow had been reduced between flies that feed on different food.

Explanation:

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A rooster with gray feathers is mated with a hen of the same phenotype. Among their offspring, 15 chicks are gray, 6 are black,
m_a_m_a [10]

Answer:

Alleles for feather colour exhibit incomplete dominance or co-dominance.

50% gray offspring + 50% black offspring

Explanation:

<em>It means that the alleles for feather colour in the hen exhibit incomplete dominance or co-dominance over one another.</em>

Assuming the allele for white colour is B, white colour will be b while the heterozygote Bb gives the gray phenotype.

Gray rooster + gray hen = 15 gray chicks, 6 black chicks and 8 white chicks.

15:6:8 is roughly 2:1:1 which is phenotypic ratio obtainable from crossing two heterozygous individuals as pointed out by Mendel.

Bb   x   Bb = 1BB, 2Bb, and 1bb

Crossing the gray rooster (Bb) with a black hen (bb):

Bb   x   bb = Bb, Bb, bb, and bb

          = 2Bb (gray):2bb (black)

50% of the offspring will be gray while the remaining 50% will be black.

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