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Sedbober [7]
3 years ago
13

7.5% of the grade has green eyes if there are 120 students in the grade how many dont have green eyes​

Mathematics
1 answer:
GREYUIT [131]3 years ago
8 0

Answer:

Step-by-step explanation:

If 7.5 % has green eyes, then 92.5% (the complement given by 100%-7.5%)  dont have green eyes. 92.5% of 120 is given by

0.925*(120)=111

111 students in the grade dont have green eyes.  

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Need soome help on this homework question thanks
SOVA2 [1]

Answer:

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Step-by-step explanation:

3 0
3 years ago
(3x^2)^-3y divided by xy
scZoUnD [109]
The number in the photo should be the answer but the problem might just be that your question was worded incorrectly.

8 0
3 years ago
(x-1)^2+(2-x)^2-3(x-5)*(x-5)
Natali5045456 [20]

Answer:

-x^2+24x-70

Step-by-step explanation:

(x-1)^2+(2-x)^2-3(x-5)*(x-5)\\=> (x - 1)^2 + (2 - x)^2 - 3(x - 5)^2\\=> x^2 - 2x + 1 + 4 - 4x + x^2 - 3(x - 5)^2\\=> x^2 - 2x + 5 - 4x + x^2 - 3(x - 5)^2\\=> x^2 - 6x + 5 + x^2 - 3(x - 5)^2\\=> 2x^2 - 6x+5 - 3(x - 5)^2\\=> 2x^2 - 6x+5 - 3(x^2 - 10x + 25)\\=> 2x^2 - 6x+5  - 3x^2+30x-75\\=> -x^2 - 6x + 5 + 30x - 75\\=> -x^2 + 24x + 5-75\\=> -x^2+24x-70

Formula used =

(a-b)^2 = a^2+ 2ab + b^2

8 0
2 years ago
What is the solution to this equation?
Fantom [35]

Answer:

x=-17

Step-by-step explanation:

<em>Original</em><em> </em><em>Equation</em><em>;</em>

<em>x</em><em>+</em><em>1</em><em>2</em><em>=</em><em>-</em><em>5</em>

<em>The</em><em> </em><em>1</em><em>2</em><em> </em><em>will</em><em> </em><em>cross</em><em> </em><em>the</em><em> </em><em>equal</em><em> </em><em>sign </em><em>so</em><em> </em><em>it </em><em>will</em><em> </em><em>become</em><em> </em><em>-</em><em>1</em><em>2</em><em>. </em><em>So</em><em> </em><em>it's</em><em> </em><em>going </em><em>to</em><em> </em><em>be</em><em>;</em>

<em>x</em><em>=</em><em>-</em><em>5</em><em>-</em><em>1</em><em>2</em>

<em>There </em><em>are</em><em> </em><em>two negative </em><em>number</em><em> </em><em>so</em><em> </em><em>you </em><em>add</em><em> </em><em>them</em><em> </em><em>and</em><em> </em><em>when</em><em> </em><em>you </em><em>add</em><em> </em><em>them</em><em> </em><em>it</em><em> </em><em>would</em><em> </em><em>still</em><em> </em><em>be</em><em> </em><em>negative</em><em>.</em><em> </em><em>And</em><em> </em><em>you </em><em>would</em><em> </em><em>have </em><em>to</em><em> </em><em>add</em><em> </em><em>them </em><em>because </em><em>when</em><em> </em><em>there </em><em>are</em><em> </em><em>two</em><em> </em><em>negative</em><em> </em><em>numbers</em><em> </em><em>without </em><em>any</em><em> </em><em>other</em><em> </em><em>sign </em><em>you </em><em>will</em><em> </em><em>have </em><em>to </em><em>add</em><em> </em><em>so</em><em> </em><em>it's </em><em>going</em><em> </em><em>to </em><em>be</em><em>;</em>

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7 0
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Mrs. Reid has picked one book so far, so now she has (1 - 9) = 8 books to choose from.
The of different books Mrs. Reid can choose now is 8, so your second number is 8.

Mrs. Reid has picked 2 book thus far, so now there are (2 - 9) = 7 books to choose from.
The of different books Mrs. Reid can choose now is 7, so your second number is 7.

To get the total number of different choices, multiply all the singular events together:

7*8*9=504\ different\ ways\ to\ bring\ 3\ books
7 0
3 years ago
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