Hi there! The answer to this problem is TRUE.
The complete statements are:
- For the single roots -1 and 2, the graph crosses the x-axis at the intercepts.
- For the double root 3, the graph touches the x-axis at the intercepts.
<h3>Missing part of the question</h3>
Complete the blanks for the function f(x) = (x + 1)(x-2)(x - 3)²
<h3>How to fill in the blanks?</h3>
The function is given as:
f(x) = (x + 1)(x-2)(x - 3)²
Express as products
f(x) = (x + 1) * (x-2) * (x - 3)²
Include the multiplicities
f(x) = (x + 1)¹ * (x-2)¹ * (x - 3)²
The factors that have a multiplicity of 1 are single roots, while the ones with multiplicity of 2 are double roots.
This means that:
- 1 multiplicity = x + 1 and x - 2
- 2 multiplicity = x - 3
The graph crosses the x-axis at 1 multiplicity and it touches the x-axis at 2 multiplicity
Hence, the terms that complete the blanks are crosses and touches, respectively
Read more about polynomials at:
brainly.com/question/4142886
#SPJ1
Five problems were missed or incorrect
Answer:
AOE = 138, EOD = 48
Step-by-step explanation:
Since AD is the diameter of the circle and goes through the middle
angle AOE + angle EOD = 180
Solving the equation (x + 138) + ( x+ 48) = 180
We get x = 0.
Given:
![f(x)=-4 \sqrt[3]{x}+6](https://tex.z-dn.net/?f=f%28x%29%3D-4%20%5Csqrt%5B3%5D%7Bx%7D%2B6)
To find:
Which table shows correct values for the function.
Solution:
Substitute x = -8 in the function:
![f(-8)=-4 \sqrt[3]{-8}+6](https://tex.z-dn.net/?f=f%28-8%29%3D-4%20%5Csqrt%5B3%5D%7B-8%7D%2B6)
Apply radical rule:
, if n is odd.
![f(-8)=-(-4 \sqrt[3]{8})+6](https://tex.z-dn.net/?f=f%28-8%29%3D-%28-4%20%5Csqrt%5B3%5D%7B8%7D%29%2B6)
![f(-8)=4 \sqrt[3]{2^3}+6](https://tex.z-dn.net/?f=f%28-8%29%3D4%20%5Csqrt%5B3%5D%7B2%5E3%7D%2B6)
![f(-8)=4 (2)+6](https://tex.z-dn.net/?f=f%28-8%29%3D4%20%282%29%2B6)
f(-8) = 14
Substitute x = -1 in the function:
![f(-8)=-4 \sqrt[3]{-1}+6](https://tex.z-dn.net/?f=f%28-8%29%3D-4%20%5Csqrt%5B3%5D%7B-1%7D%2B6)
Apply radical rule:
, if n is odd.
![f(-1)=-(-4 \sqrt[3]{1})+6](https://tex.z-dn.net/?f=f%28-1%29%3D-%28-4%20%5Csqrt%5B3%5D%7B1%7D%29%2B6)
![f(-1)=4 \sqrt[3]{1^3}+6](https://tex.z-dn.net/?f=f%28-1%29%3D4%20%5Csqrt%5B3%5D%7B1%5E3%7D%2B6)
![f(-1)=4 (1)+6](https://tex.z-dn.net/?f=f%28-1%29%3D4%20%281%29%2B6)
f(-8) = 10
Substitute x = 0 in the function:
![f(0)=-4 \sqrt[3]{0}+6](https://tex.z-dn.net/?f=f%280%29%3D-4%20%5Csqrt%5B3%5D%7B0%7D%2B6)
![f(0)=0+6](https://tex.z-dn.net/?f=f%280%29%3D0%2B6)
f(0) = 6
Substitute x = 8 in the function:
![f(8)=-4 \sqrt[3]{8}+6](https://tex.z-dn.net/?f=f%288%29%3D-4%20%5Csqrt%5B3%5D%7B8%7D%2B6)
![f(8)=-4 \sqrt[3]{2^3}+6](https://tex.z-dn.net/?f=f%288%29%3D-4%20%5Csqrt%5B3%5D%7B2%5E3%7D%2B6)
![f(8)=-4 (2)+6](https://tex.z-dn.net/?f=f%288%29%3D-4%20%282%29%2B6)
f(8) = -2
Therefore table 3 is shows correct values for the function.