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daser333 [38]
3 years ago
7

Sara needs to pack 108 stalks of roses, 81 stalks of lilies, and 54 stalks of orchids into identical baskets so that each type o

f flower is equally distributed among the baskets. Find the largest number of the basket that can be packed
Mathematics
1 answer:
polet [3.4K]3 years ago
4 0

Answer:

54

Step-by-step explanation:

There are 108 roses, 81 lilies and 54 orchids.

The problem is asking that every basket contain the same number for that type of flower.

So if I put one of each flower in each basket, I will get 54 baskets at the most.

Sounds correct to you?

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The quantity demanded x each month of Russo Espresso Makers is 250 when the unit price p is $138. The quantity demanded each mon
Stells [14]

Answer:

(a)D(q)=\frac{-1}{25} q+148

(b)S(q)=\frac{1}{50}q+58

(c)p_{*} =88\\\\q_{*} =1500

Step-by-step explanation:

(a) For the demand equation D(q) we have

<em>P1: 138 Q1: 250</em>

<em>P2: 108 Q2: 1000</em>

We can find <u><em>m</em></u>, which is the slope of the demand equation,

m=\frac{p_{2} -p_{1} }{q_{2} -q_{1} }=\frac{108-38}{1000-250} =\frac{-30}{750}=\frac{-1}{25}

and then we find b, which is the point where the curve intersects the y axis.

We can do it by plugging one point and the slope into the line equation form:

y=mx+b\\\\D(q)=mq+b\\\\138=\frac{-1}{25}(250) +b\\\\138=-10+b\\\\138+10=b=148

<em>With b: 148 and m: -1/25 we can write our demand equation D(q)</em>

D(q)=\frac{-1}{25} q+148

(b) to find the supply equation S(q) we have

<em>P1: 102 Q1: 2200</em>

<em>P2: 102 Q2: 700</em>

<em></em>

Similarly we find <em>m</em>, and <em>b</em>

m=\frac{p_{2} -p_{1} }{q_{2} -q_{1} }=\frac{72-102}{700-2200} =\frac{-30}{-1500}=\frac{1}{50}

y=mx+b\\\\D(q)=mq+b\\\\72=\frac{1}{50}(700) +b\\\\72=14+b\\\\72-14=b=58\\

<em>And we can write our Supply equation S(q):</em>

S(q)=\frac{1}{50}q+58

(c) Now we may find the equilibrium quantity q* and the equilibrium price p* by writing <em>D(q)=S(q)</em>, which means the demand <u><em>equals</em></u> the supply in equilibrium:

D(q)=S(q)\\\\\frac{-1}{25}q+148=\frac{1}{50}q+58\\\\

148-58=\frac{1q}{50} +\frac{1q}{25} \\\\90= \frac{1q}{50} +\frac{2q}{50}\\\\90=\frac{3q}{50}\\ \\q=1500\\\\

We plug 1500 as q into any equation, in this case S(q) and we get:

S(q)=\frac{1}{50}q+58\\\\S(1500)=\frac{1}{50}(1500)+58\\\\S(1500)=30+58\\\\S(1500)=88

Which is the equilibrium price p*.

8 0
3 years ago
HELPPPPP!!! Can you TEACH ME HOW TO DO THIS and will give b
IRINA_888 [86]

Answer:

yh I can help the answer is 185/1000 bc u have to convert it as a fraction and u can simplify it by 5 then the answer will be 37/200 plz try this if not I will tell u something else

5 0
2 years ago
5637 rounded to the nearest thousand is what
sesenic [268]
6000                
 hope it helps :)
5 0
3 years ago
Read 2 more answers
6 people sharing 40 lbs of gold evenly. How many do they get? Then subtract 1 2/3 from the result of the problem above &amp; sim
r-ruslan [8.4K]

Answer: 6

Step-by-step explanation:

Given Data:

Number of people = 6

Amount of Gold to be shared = 40lbs

Subtract 2/3 from your answer.

Therefore

If six people are to share 40lbs of gold evenly

= 40lbs / 6

Divide through by 2

= 20lbs / 3

= 20lbs / 3 - 2/3

= 18/3

= 6

Each person would get approximately 6lbs of gold

7 0
2 years ago
Read 2 more answers
HELP ME I NEED SOMEONE TO SHOW WORK AND AWNSER QUESTION ITS TIMED PLEASE HURRY 30 POINTS FOR IT!
vodka [1.7K]

Answer:

Just like how we did the other one, you will do the same thing. Hope this helps, thank you !!

3 0
3 years ago
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