A = 4,
we denote one side of the rectangle with
a
, and the other with
b
we can write, that:
a
⋅
b
=
16
so we can write, that
b
=
16
a
Now we can write perimeter
P
as a function of
a
P
=
2
⋅
(
a
+
16
a
)
We are looking for the smallest perimeter, so we have to calculate derivative:
P
(
a
)
=
2
a
+
32
a
P
'
(
a
)
=
2
+
(
−
32
a
2
)
P
'
(
a
)
=
2
−
32
a
2
=
2
a
2
−
32
a
2
The extreme values can only be found in points where
P
'
(
a
)
=
0
P
'
(
a
)
=
0
⇔
2
a
2
−
32
=
0
2
a
2
−
32
=
0
x
a
2
−
16
=
0
×
x
.
.
a
2
=
16
×
×
x
a
=
−
4
or
a
=
4
Since, length is a scalar quantity, therefore, it cannot be negative,
When
a
=
4
,
b
=
16
4
b
=
4
Answer:
Mode is 20.
Step-by-step explanation:
Mode is the value or values in the data set that occurs most frequently.
{12, 12.50, 13, 18.50, 20, 20}
20 is the number that occurs most frequently.
hope this helps and is right :)
first to find average age add all the ages divide by number of ages 4
5+4=9
9+6=15
15+39=54
54/4=13.5
For standard deviation find the mean/average
13.5
then subtract the mean from each number/age
5-13.5=-8.5
4-13.5=-9.5
6-13.5=-7.5
39-13.5=25.5
then square each number
-8.5^2=-72.25
-9.5^2=-90.25
-7.5^2=-56.25
25.5^2=650.25
then find the mean/average of the new numbers
-72.25+-90.25+-56.25+650.25=431.5
431.5/4=107.85
then take the square root of the new mean/average

Answer:
(d) 71°
Step-by-step explanation:
The desired angle in the given isosceles triangle can be found a couple of ways. The Law of Cosines can be used, or the definition of the sine of an angle can be used.
<h3>Sine</h3>
Since the triangle is isosceles, the bisector of angle W is an altitude of the triangle. The hypotenuse and opposite side with respect to the divided angle are given, so we can use the sine relation.
sin(W/2) = Opposite/Hypotenuse
sin(W/2) = (35/2)/(30) = 7/12
Using the inverse sine function, we find ...
W/2 = arcsin(7/12) ≈ 35.685°
W = 2×36.684° = 71.37°
W ≈ 71°
<h3>Law of cosines</h3>
The law of cosines tells you ...
w² = u² +v² -2uv·cos(W)
Solving for W gives ...
W = arccos((u² +v² -w²)/(2uv))
W = arccos((30² +30² -35²)/(2·30·30)) = arccos(575/1800) ≈ 71.37°
W ≈ 71°
The correct answer is C).