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NemiM [27]
3 years ago
14

The solution is {-8, 3} but I’m not sure how to graph it on a line, is it A B C or D?

Mathematics
1 answer:
shtirl [24]3 years ago
8 0

Answer:

-8 < x< 3

Step-by-step explanation:

|2x+5| <11

there are two solutions, one positive and one negative ( remember to flip the inequality for the negative)

2x+5 <11  and   2x+5 > -11

Subtract 5 from each side

2x+5-5 < 11-5 and    2x+5-5 > -11-5

2x< 6           and           2x>-16

Divide by 2

2x/2 <6/2        and       2x/2 >-16/2

x <3                  and             x>-8

-8 < x< 3

x is less than 3 and x is greater than -8

open circles and -8 and 3 and a line between

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ioda
The answer is 8
Here's why:
{ ( \frac{( {6}^{7}) \times ( {3}^{3})  }{(  {6}^{6}) \times ( {3}^{4}  ) } )}^{3}  =   \\ ( \frac{6}{3} ) ^{3}  =  \\ \frac{216}{27}  = 8
The exponents are subtracted one from another when divided.
\frac{ a ^{b} }{ {a}^{c} } =  {a}^{b - c}
We can look at the problem this way:
( \frac{6^{7} }{6 ^{6} }  \times  \frac{3^{3} }{ {3}^{4} } ) = (6^{7 - 6}  \times  {3}^{3 - 4} ) =  \\ ({6}^{1}  \times  {3}^{ - 1} )
Since we have the power of -1 on the 3, we apply this rule:
{a}^{ - b}  =  \frac{1}{ {a}^{b} }
Also this rule because we have the power of 1 on the 6:
{a}^{1}  = a
Then we get this:
(6 \times  \frac{1}{3} )^{3}  = ( \frac{6}{3} )^{3}
We apply the rule:
( \frac{a}{b}) ^{c}   =  \frac{ {a}^{c} }{ {b}^{c} }
We get this:
\frac{{6}^{3} }{ {3}^{3} } =  \frac{216}{27}  = 8
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3 years ago
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1 - 2/3 - 1/4
= 1 - 8/12 - 3/12
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