All categories

3 years ago

A number is multiplied by 5. If 12 is added to the product you get 37.

Mathematics

1 answer:

Korolek [52]3 years ago

5 0

5x+12=37

5x=25

x=5

I hope this helps

You might be interested in

What is the remainder of 6099 divided by 7

tino4ka555 [31]

Remainder of 6099 Divided by 7? The quotient (integer division) of 6099/7 equals 871; the remainder (“left over”) is 2.

8 0

1 year ago

Enter the coordinates of the point

agasfer [191]

Answer: $(\frac{\sqrt{3} }{2} ,-\frac{1}{2} )$

Step-by-step explanation:

this forms a 30 degree reference angle

and this is in the 4th quadrant

When the angle is 30 degrees, the coordinates are:

$(\frac{\sqrt{3} }{2} ,-\frac{1}{2} )$

6 0

2 years ago

Nan rode the roller coaster 8 times, which was twice as many times as she rode the F erris wheel

lyudmila [28]

So she rode the Ferris Wheel 4 times. 8/2= 4

8 0

3 years ago

Jacob Lee is a frequent traveler between Los Angeles and San Diego. For the past month, he wrote down the flight times in minute

valkas [14]

Solution :

We know that

$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

We need to find the critical values.

We know k = 3 , N = 35, α = 0.05

d.f.N = k - 1

= 3 - 1 = 2

d.f.D = N - k

= 35 - 3 = 32

SO the critical value is 3.295

The mean and the variance of each sample :

Goust Jet red Cloudtran

$\overline X_1 =50.5$ $\overline X_2 =50.07143$ $\overline X_3 =55.71429$

$s_1^2=19.96154$ $s_2^2=14.68681$ $s_3^2=36.57143$

The grand mean or the overall mean is(GM) :

$\overline X_{GM}=\frac{\sum \overline X}{N}$

$=\frac{51+51+...+49+49}{35}$

= 52.1714

The variance between the groups

$s_B^2=\frac{\sum n_i\left( \overline X_i - \overline X_{GM}\right)^2}{k-1}$

$=\frac{\left[14(50.5-52.1714)^2+14(52.07143-52.1714)^2+7(55.71426-52.1714)^2\right]}{3-1}$

$=\frac{127.1143}{2}$

= 63.55714

The Variance within the groups

$s_W^2=\frac{\sum(n_i-1)s_i^2}{\sum(n_i-1)}$

$=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

$=\frac{669.8571}{32}$

= 20.93304

The F-test statistics value is :

$F=\frac{s_B^2}{s_W^2}$

$=\frac{63.55714}{20.93304}$

= 3.036212

Now since the 3.036 < 3.295, we do not reject the null hypothesis.

So there is no sufficient evidence to support the claim that there is a difference among the means.

The ANOVA table is :

Source Sum of squares d.f Mean square F

Between 127.1143 2 63.55714 3.036212

Within 669.8571 32 20.93304

Total 796.9714 34

3 0

2 years ago

Help me I really need to get this done

posledela

Answer:

It’s the second one

Step-by-step explanation:

6 0

2 years ago