Answer:
Standard form of equation for a hyperbola with horizontal transverse axis:
(x-h)^2/a^2-(y-k)^2/b^2=1, (h,k)=(x,y) coordinates of center
For given hyperbola:
x-coordinate of center=(9+1)/2=5 (use midpoint formula)
y-coordinate of center=1
center: (5,1)
length of horizontal transverse axis=8 (from 1 to 9)=2a
a=4
a^2=16
..
Foci
2c=9 ( from 1 to 10)
c=4.5
..
c^2=a^2+b^2
b^2=c^2-a^2=20.25-16=4.25
..
Equation of hyperbola:
(x-5)^2/16-(y-1)^2/4.25=1
Answer:
The vertex of a quadratic equation corresponds to the point where the maximum or minimum value is located.
If the function has a positive leading coefficient, the vertex corresponds to the minimum value.
If it has a negative leading coefficient, the vertex corresponds to the maximum valuevalue
If the vertex is located at
(–2, 0)
The possibilities are
y = (x-2)^2
or,
y = - (x-2)^2
Since the problem tells us the answer, we adopt the positive values
Answer:
y = (x-2)^2
See attached picture
Answer:
Perimeter: 26 units
Area: 36 units
Step-by-step explanation:
EH = 4 units
HG = 9 units
GF = 4 units
FE = 9 units
Add them all up to find the perimeter
4 + 4 + 9 + 9 = 26
Then multiply the side by length to get the area
4 * 9 = 36
The answer is .001...................................