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vagabundo [1.1K]
3 years ago
5

You roll a number cube twice what is the probability of rolling a 2

Mathematics
2 answers:
Molodets [167]3 years ago
8 0

Answer:

i think its 1 out of 6 or 2 out of 12 depending on the way you meant the question  im pretty sure this is right correct me if iam wrong



Step-by-step explanation:


Colt1911 [192]3 years ago
4 0

The probability of getting a 5 from the first rolling is 1/6.  The probability of getting an even number  is 1/2 (= 1/6 (for a 2) + 1/6 (for a 4) + 1/6 (for a 6)).  As the two rollings are independent, you can just multiply two probability values to come up with a final answer.  That is, (1/6)·(1/2) = 1/12.

Note that I did not write this. This answer comes from Wyzant. I am only linking this to you so that you'll get the answer quickly.

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Which angle refers to the same angle as \angle DAC∠DACangle, D, A, C?
Arturiano [62]

Answer:

Option

Step-by-step explanation: The way tell what the answer is are the similar lines. The single yellow line helps indicate that it's a similar angle.

3 0
2 years ago
How many permutations are possible for 11 objects taken 7 at a time? 330 5,040 237,600 1,663,200
USPshnik [31]

11 choose 7 is equal to 11 choose 4. 11*10*9*8/4/3/2=330.


5 0
3 years ago
If Log 4 (x) = 12, then log 2 (x / 4) is equal to <br>A. 11 <br>B. 48 <br>C. -12 <br>D. 22
klio [65]
C I guess sorry if I get you a low score
6 0
3 years ago
I need help can I don’t know how to do this problem
Elden [556K]

Answer:

a ^ (1/12)

Step-by-step explanation:

a ^ (1/3)

---------------

a ^ (1/4)

We know that b^ c / b^ d = b ^ (c-d)

a^ (1/3 - 1/4)

getting a common denominator

1/3 *4/4 - 1/4*3/3 = 4/12 - 3/12

a^ (4/12 - 3/12)

a ^ (1/12)

7 0
2 years ago
the admission fee for a charity event is 7 dollars for children and 10 dollars for adults the event was attended by 700 people a
ollegr [7]
Given:
$7/child
$10/adult
Total people = 700
Total money = $6,400

First, make two equations.
Let a = # of adults & Let c = # of children.
Let p = total people

1.      a+c = 700
2.  10a+7c = 6,400

Then, rearrange the equation to solve for a variable.
c = 700-a

Substitute (700-a) for c, or the # of children in the second equation.
10a+(700-a) = 6400
9a+700 = 6400
9a+700-700 = 6400-700
9a = 5700
9a/9 = 5700/9 
a = 633\frac{1}{3}  = # of adults attended

700-633\frac{1}{3} = c = 66 \frac{2}{3} = # of children attended


4 0
3 years ago
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