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Burka [1]
3 years ago
7

What is the equation of this line?

Mathematics
2 answers:
dezoksy [38]3 years ago
7 0

Answer:

A. y = 2x - 3

Explaination:

It can't be negative because then the slope would be going downward from left to right, this line is going upwards. Also, the steepness of the slope proves it is a slope of 2 because a slope of 1/2 isn't very steep. You can also count 1 unit over and look how much the line changes to find the slope.

grandymaker [24]3 years ago
3 0

Answer:

A

Step-by-step explanation:

X intercept : (3/2 , 0)

Y intercept : (0 , -3)

Slope: m=2

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C.

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If a = 9 and c = 20, the measure of ∠B = ____ degrees (to the nearest tenth).
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Answer: We are missing some data here, but it appears to be a right triangle question. Assuming that triangle ABC is a right triangle, the measure of angle B would be about 63.26 degrees.

If you draw a right triangle ABC with the given information, you will see that we have an adjacent side and hypotenuse with regard to angle B.

Therefore, we can write and solve the following cosine ratio.

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Each cupcake cost $1.50
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A jumping spider's movement is modeled by a parabola. The spider makes a single jump from the origin and reaches a maximum heigh
aleksklad [387]

The spider's movement is an illustration of a parabola.

  • The equation of a parabola is: \mathbf{y = -\frac{1}{160}(x - 40) + 10}
  • The focus of a parabola is: (40,-30)
  • The axis of symmetry is: \mathbf{x = 40}
  • The directrix is:\mathbf{y = 50}

<u>(a) The equation</u>

The spider passes through the origin.

So, we have:

\mathbf{(x,y) = (0,0)}

The spider jumps to a maximum height of 10mm, midway 80mm.

So, the vertex is:

\mathbf{(h,k) =  (40,10)}

The equation of a parabola is:

\mathbf{y = a(x - h)^2 + k}

So, we have:

\mathbf{0 = a(0 - 40)^2 + 10}

Subtract 10 from both sides

\mathbf{a(0 - 40)^2 =- 10}

\mathbf{1600a =- 10}

Solve for a

\mathbf{a =- \frac{1}{160}}

Substitute \mathbf{a =- \frac{1}{160}} and \mathbf{(h,k) =  (40,10)} in \mathbf{(h,k) =  (40,10)}

\mathbf{y = -\frac{1}{160}(x - 40) + 10}

<u>(b) The focus, directrix and the axis of symmetry</u>

The focus of a parabola is:

\mathbf{Focus= (h, k + p)}

Where:

\mathbf{p = \frac{1}{4a}}

So, we have:

\mathbf{p = \frac{1}{4 \times -1/160}}

\mathbf{p = -\frac{160}{4}}

\mathbf{p = -40}

So, we have:

\mathbf{Focus = (40,10-40)}

\mathbf{Focus = (40,-30)}

The axis of symmetry is:

\mathbf{x = h}

So, we have:

\mathbf{x = 40}

The directrix is:

\mathbf{y = k - p}

\mathbf{y = 10 + 40}

\mathbf{y = 50}

Read more about parabolas at:

brainly.com/question/25237745

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Answer:

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