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3 years ago

13

Georgia wants to purchase a piece of fabric that is between 64 and 68 inches long. She can choose between three pieces of fabric

. Choice A is 5 3/4 feet long. Choice B is 5 1/2 feet long. Choice C is 5 1/4 feet long. Which fabric should Georgia purchase?

2 answers:

egoroff_w [7]3 years ago

7 0

1 foot equals 12 inches. You should convert choice A, B, C to foot unit.

Choice A
5 3/4 × 12
= 23/4 × 12
= (23 × 12)/4
= 276/4
= 69 inches

Choice B
5 1/2 × 12
= 11/2 × 12
= (11 × 12)/2
= 66 inches

Choice C
5 1/4 × 12
= 21/4 × 12
= (21 × 12)/4
= 252/4
= 63 inches

Fabric which is between 64 and 68 is choice B

sineoko [7]3 years ago

6 0

The answer is B. Mark as brainliest if this helped you out :). (It would be 66 inches long)

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Answer:

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Step-by-step explanation:

s + g = 14

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125( 14 - g ) + 75g = 1500

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2 years ago

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3 years ago

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Ulleksa [173]

Answer:

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5 0

3 years ago

I need to know the improper fractions answers for:

zmey [24]

Answer:

Part 1) $x=\frac{15}{2}\ units$

Part 2) $z=\frac{15\sqrt{3}}{2}\ units$

Part 3) $y= \frac{15\sqrt{3}}{4}\ units$

Part 4) $b= \frac{45}{4}\ units$

Step-by-step explanation:

step 1

Find the value of x

In the large right triangle

$cos(60^o)=\frac{x}{15}$ ----> by CAH (adjacent side divided by the hypotenuse)

Remember that

$cos(60^o)=\frac{1}{2}$

substitute

$\frac{1}{2}=\frac{x}{15}$

solve for x

$x=\frac{15}{2}\ units$ ---> improper fraction

step 2

Find the value of z

In the large right triangle

Applying the Pythagorean Theorem

$15^2=x^2+z^2$

substitute the value of x

$15^2=(\frac{15}{2})^2+z^2$

solve for z

$z^2=15^2-(\frac{15}{2})^2$

$z^2=225-\frac{225}{4}$

$z^2=\frac{675}{4}$

$z=\frac{\sqrt{675}}{2}\ units$

simplify

$z=\frac{15\sqrt{3}}{2}\ units$

step 3

Find the value of y

In the right triangle of the right

$sin(30^o)=\frac{y}{z}$ ---> by SOH (opposite side divided by the hypotenuse)

substitute the given values of y and z

Remember that

$sin(30^o)=\frac{1}{2}$

so

$\frac{1}{2}=y:\frac{15\sqrt{3}}{2}$

solve for y

$\frac{1}{2}= \frac{2y}{15\sqrt{3}}$

$y= \frac{15\sqrt{3}}{4}\ units$

step 4

Find the value of b

In the right triangle of the right

$cos(30^o)=\frac{b}{z}$ ---> by CAH (adjacent side divided by the hypotenuse)

substitute the given values of y and z

Remember that

$cos(30^o)=\frac{\sqrt{3}}{2}$

so

$\frac{\sqrt{3}}{2}=b:\frac{15\sqrt{3}}{2}$

solve for y

$\frac{\sqrt{3}}{2}= \frac{2b}{15\sqrt{3}}$

$b= \frac{45}{4}\ units$

7 0

3 years ago