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3 years ago

Solve for x. x - 7 = 25

Mathematics

2 answers:

andre [41]3 years ago

6 0

Answer:

x = 32

Step-by-step explanation:

x - 7 = 25

To solve equations, you do the some thing to both sides to isolate x.

After adding 7 to both sides we have:

x = 32

gizmo_the_mogwai [7]3 years ago

4 0

Answer:

x = 32

Step-by-step explanation:

⇒ Isolate the variable x by adding 7 to both sides:

x – 7 + 7 = 25 + 7

⇒ Evaluate the equation to finally get:

x = 32

Hope this helps! :)

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For the second week of June, Kevin Adams worked 46 hours. Kevin earns $18.40 an hour. His employer pays overtime for all hours w

zimovet [89]

Answer:

$165.60 overtime money only

$736 regular time only

added together (gross income)

$901.60

Step-by-step explanation:

46hrs
18.40 an hr
hrs over 40 = overtime= *1.5

To figure out if there is any overtime here, we subtract.

46-40= 6hrs of overtime

To figure out the amount of cash gained for regular time, we multiply.

40*18.40 = 736

----------------

We need to know how much money is paid per overtime hour.

18.40*1.5 = 27.60

To figure out the amount of cash gained during overtime, we multiply.

6*27.60 = 165.60

add for gross income (total earnings)

165.60+736 = 901.60

7 0

3 years ago

Y=5(x-2)(x+1) in standard form

Harrizon [31]

5(x²+x-2x-2)
5(x²-x-2)
5x²-5x-10

you can also simplify to x²-x-2.

6 0

3 years ago

Michael buys a ball for 5.50 and a flashlight for 3.65. If he has 10.00 how much change we’ll he receive

Sveta_85 [38]

Answer:

.85 cents

Step-by-step explanation:

3 0

3 years ago

An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concen

devlian [24]

Answer:

(a) A 95% confidence interval for the population mean is [433.36 , 448.64].

(b) A 95% upper confidence bound for the population mean is 448.64.

Step-by-step explanation:

We are given that article contained the following observations on degrees of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:

420, 425, 427, 427, 432, 433, 434, 437, 439, 446, 447, 448, 453, 454, 465, 469.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = $\frac{\sum X}{n}$ = 441

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 14.34

n = sample size = 16

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.131 < $t_1_5$ < 2.131) = 0.95 {As the critical value of t at 15 degrees of

freedom are -2.131 & 2.131 with P = 2.5%}

P(-2.131 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.131) = 0.95

P( $-2.131 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.131 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X -2.131 \times {\frac{s}{\sqrt{n} } }$ , $\bar X +2.131 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $441-2.131 \times {\frac{14.34}{\sqrt{16} } }$ , $441+2.131 \times {\frac{14.34}{\sqrt{16} } }$ ]

= [433.36 , 448.64]

(a) Therefore, a 95% confidence interval for the population mean is [433.36 , 448.64].

The interpretation of the above interval is that we are 95% confident that the population mean will lie between 433.36 and 448.64.

(b) A 95% upper confidence bound for the population mean is 448.64 which means that we are 95% confident that the population mean will not be more than 448.64.

6 0

3 years ago

Alex plays hockey. He needs to buy a new hockey stick and skates. The hockey stick costs $80 and new skates cost $300. Alex has

Umnica [9.8K]

The answer would be 303.62 if I’m not mistaken

6 0

3 years ago