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erik [133]
2 years ago
13

A small bag of jelly beans contains 2 lemon, 5 cherry, 1 lime, and 4 blueberries jelly beans. If Evin chooses a jelly bean from

the bag without looking, what is the probability it will be cherry or blueberry?
Mathematics
2 answers:
jeka942 years ago
6 0
The correct answer should be 75%
VashaNatasha [74]2 years ago
4 0

Answer:

75%

Step-by-step explanation:

lime and cherry/ total jelly beans

(5+4)/(2+5+1+4)=9/12=0.75=75%

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2/3 = 1.5

Step-by-step explanation:

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2 years ago
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A tentmaker has 60,000 tents in stock. The Army decides to order 200 tents
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300

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7 0
3 years ago
(a) Describe a property specific to squares that is not a property specific to rectangles.
blondinia [14]

Answer:

Step-by-step explanation:

(a) A square has all the 4 sides being equal while a rectangle has four sides, with the opposite sides being parallel and the same length.

(b) The diagonals bisect the angles , the diagonals are perpendicular bisectors of each other

(c) A square has two pairs of parallel sides, four right angles, and all four sides are equal while the angles of a parallelogram are not right angles

(d) a rhombus can be a rectangle (if the angles of the rhombus are all 90 degrees), and a rectangle can be a rhombus (if the sides of the rectangle are all equal length). Opposite sides are parallel.

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5 0
2 years ago
Read 2 more answers
Whajsoska help pls omgggggg ​
noname [10]

Answer:

I can answer the first one the other 2 I can't make out.

Step-by-step explanation:

Firstly,

1) They are the same since they add one to the row every time

2) They are different because Megan's pattern is that they only count the first column in orange, and Kyle's pattern counts the number of blocks in each row.

3) They have the same number of blocks just in different colors in rows and columns.

8 0
2 years ago
Using a proportion, what can you infer about the number of households in her town that have more than three children?
eduard

Answer:

About 296 households have more than three children.

Step-by-step explanation:

The complete question is:

Carmen used a random number generator to simulate a survey of how many children live in the households in her town. There are 1,346 unique addresses in her town with numbers ranging from zero to five children. The results of 50 randomly generated households are shown below. Children in 50 Households Number of Children Number of Households 0 5 1 11 2 13 3 10 4 9 5 2 Using a proportion, what can you infer about the number of households in her town that have more than three children? About 242 households have more than three children. About 269 households have more than three children. About 296 households have more than three children. About 565 households have more than three children.

Solution:

The data provided for the number of children and number of households is:

Number of Children (<em>X</em>)          Number of Households (<em>f</em> (X))

               0                                                   5

               1                                                    11

               2                                                   13

               3                                                   10

               4                                                    9

               5                                                    2

           TOTAL                                             50

Compute the probability of households having more than three children as follows:

P (More than 3 children) = P (4 children) + P (5 children)

                                        =\frac{9}{50}+\frac{2}{50}

                                        =\frac{11}{50}

                                        =0.22

Let the random variable <em>Y</em> be defined as the number of households having more than three children.

The probability of the random variable <em>Y </em>is, <em>p</em> = 0.22.

The entire population, i.e. total number of addresses in Carmen's town with numbers ranging from zero to five children, consists of <em>N</em> = 1,346 households.

Compute the expected number of households having more than three children as follows:

E(Y) =N\times p

         =1346\times 0.22\\=296.12\\\approx 296

Thus, about 296 households have more than three children.

4 0
2 years ago
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