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3 years ago

2. Graph the solution set to the following inequality: 7-y<2x

Mathematics

1 answer:

nirvana33 [79]3 years ago

7 0

Step-by-step explanation:

First solve for y,

7-y<2x

7-2x<y

y>-2x+7

your y intercept would be (0,7)

and your slope would be -2/1 so, you go down 2 and 1 to the right.

Since this is a greater than symbol, we have to shade above the line and the line would also be a dotted line.

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A motor club has estimated that a 325 mile car trip will take 6 1/2 hours. What is the club assuming to be the average speed mil

In-s [12.5K]

Answer:

The average speed that the club is assuming is 50 miles per hour

Solution:

We know that Distance = Speed × Time.

Here it is given that distance is 325 miles and the time to cover 325 miles is $6_{2}^{1}$ hours which is equal to $\frac{13}{2}$ hours.

Now to find the average speed mile per hour we use the formula

$\begin{aligned} \text { Speed } &=\frac{\text { Distance }}{\text { time }} \\ &=\frac{325}{\frac{13}{2}} \\ &=\frac{325 \times 2}{13} \end{aligned}$

By cancelling 325 by 13 we get 25

= 25 × 2

= 50 miles per hour

Thus the average speed that the club is assuming is 50 miles per hour.

3 0

3 years ago

Which of the following expresses 16 + 36 by using the GCF of the two numbers?

sergij07 [2.7K]

16 + 36 = 52 so the answer would be A) 4(4 + 9) because that equals 52 as well.

6 0

3 years ago

Read 2 more answers

What is the sum of 7x/(x^2-4) and 2/(x+2)

ioda

Answer:

The answer is 9x-4/(x+2)(x-2)

7 0

3 years ago

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Please help fast i will give you the most Brainly what would n = 3(n+7)=48

neonofarm [45]

Answer:

n = 9

Step-by-step explanation:

3(n+7)=48

distribute

3n +21 = 48

subtract 21 from each side

3n = 48-21

3n = 27

divide by 3

3n/3 = 27/3

n = 9

5 0

3 years ago

Lizzie rolls two dice. What is the probability that the sum of the dice is:

zhenek [66]

Answer:

$A.\ \dfrac{1}{3}\\B.\ \dfrac{5}{12}\\C.\ \dfrac{7}{36}\\$

Step-by-step explanation:

Total outcomes possible: 36

A. Divisible by 3

Possible options are:

3, 6, 9 and 12.

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

Possible outcomes for 9 are: {(3,6), (4,5), (5,4),(6,3)} Count 4

Possible outcomes for 12 are: {(6,6)} Count 1

Total count = 2 + 5 + 4 + 1 = 12

Probability of an event E can be formulated as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(A) = \dfrac{12}{36} = \dfrac{1}{3}$

B. Less than 7:

Possible sum can be 2, 3, 4, 5, 6

Possible cases for sum 2: {(1,1)} Count 1

Possible cases for sum 3: {(1,2), (2,1)} Count 2

Possible cases for sum 4: {(1,3), (3,1), (2,2)} Count 3

Possible cases for sum 5: {(1,4), (2,3), (3,2),(4,1)} Count 4

Possible cases for sum 6: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

Total count = 1 + 2 + 3 + 4 + 5 = 15

$P(B) = \dfrac{15}{36} = \dfrac{5}{12}$

C. Divisible by 3 and less than 7:

$P(A \cap B) = \dfrac{n(A\cap B)}{\text{Total Possible outcomes}}$

Here, common cases are:

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

$P(A \cap B) = \dfrac{7}{\text{36}}$

5 0

3 years ago