There are four rectangles and 2 squares.
Let’s start with the four rectangles.
4 [ 2x(x)]
4 [ (2*7)(7)] = 392 cm^2
______________
Next, let’s find the SA for the two squares.
2 [(2x)^2]
** I need to be clear that both the 2 and the x in the parentheses are squared because the square, of course, is a “perfect square”. This was probably obvious and needless to say, haha oh well.
Next step: plug in values
2 [ [2(7)]^2 ] = 392 cm^2
TOTAL: 392+392 = 784 cm^2
Wow I should have realized the the 4 rectangles are the area as the two squares.
Good luck to you!
If you have any other math questions, I can try my best to answer them. Just send me a comment or whatever works.
80% because I did the math
Perimeter is legnth +legnth + width + width or
P=2L+2W
L=2W
subsitute L=2W for L in P=2L+2W
P=2(2W)+2W
P=4W+2W
P=6W
we know that Perimiter=30 so
30=6W
divide both sides by 6
5=Width
subsitute W=5 for W in L=2W
L=2(5)
L=10
to check
10=2(10)+2(5)
30=20+10
30=30
checks
Legnght=10
Width=5
What is the middle of 6 and 12- 6, 7, 8, 9, 10, 11, or 12?
To calculate the area of a triangle you need the base & the altitude to this base:
Area triangle = 1/2(B x H)
Let's draw the altitude A intersecting BC in H. WE get now a right triangle AHB. We know AG = 9.2 we know the angle B =27°, so we can find the altitude AH through trigonometry :
sin(B) = opposite side over hypotenuse
sin(27°) = AH/AB==> sin(27°) =0.454 ==0.454= AH/9.2==>AH =0.454*9.2
AH = 4.177
Area triangle ABC = (1/2) * 11.9 * 4.177= 24.85
