<h3>
Answer: angle X = 70.5 degrees</h3>
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Work Shown:
Law of Cosines
c^2 = a^2 + b^2 - 2ab*cos(C)
22^2 = 20^2 + 18^2 - 2*20*18*cos(X)
484 = 724 - 720*cos(X)
484 + 720*cos(X) = 724
720*cos(X) = 724 - 484
720*cos(X) = 240
cos(X) = 240/720
cos(X) = 1/3
X = arccos(1/3)
X = 70.528779
X = 70.5
Make sure your calculator is in degree mode.
Answer:
-3
Step-by-step explanation:
log 1/3 27= 1/3^x=27 this means we have to simplify it. 1/3= 3^-1 power. Thus, (3^-1)^x=3^3. This is equal to 3^-x=3^3 therefore x=-3
This is a typical radioactive decay problem which uses the general form:
A = A0e^(-kt)
So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:
A = 192e^(-0.015*55)
<em>A = 84 mg</em>
Answer:
1) 33.33%
2) 16.66%
Step-by-step explanation:
1) Since multiples of 3 in 1,2,3,4,5,6 include and limited to 3 and 6. This means that 2 / 6 or 1 / 3. This fraction is equal to 33.33%.
2) Since multiples of 4 in 1,2,3,4,5,6 include and limited to only 4. This means that 1/6 and this fraction is equal to 16.66%.
Answer:
23, 25, 27
Step-by-step explanation:
first integer will be X, second will be (X+2), and the third will be (X+4). They will all be summed up and set equal to 75.
combine like terms:
subtract 6:
divide by 3 to find value of X:
plug in X in o red der to finger the rest of the integers.
(X+2)= (23+2)=25
(X+4)= (23+4)=27
