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ArbitrLikvidat [17]
3 years ago
13

(X2y3)1/2(x2y3)1/3=xa/3ya/2 where a is constant, is true for all positive values of c and y, what is value of a?

Mathematics
1 answer:
Slav-nsk [51]3 years ago
8 0
The answer is <span>a=<span><span><span>√<span><span>x3</span><span>y5</span></span></span><span> or </span></span>a</span></span>=<span>−<span>√<span><span>x3</span><span>y<span>5</span></span></span></span></span>
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the graphy below shows the relationshio between the numbers of calories and the total amount in fat in different types of sandwi
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The points have a positive trend and are most likely linear

Answer (C)

Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
Solve the system by using a matrix equation (Picture provided)
Katyanochek1 [597]

Answer:

Option b is correct (8,13).

Step-by-step explanation:

7x - 4y = 4

10x - 6y =2

it can be represented in matrix form as\left[\begin{array}{cc}7&-4\\10&-6\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{c}4\\2\end{array}\right]

A= \left[\begin{array}{cc}7&-4\\10&-6\end{array}\right]

X= \left[\begin{array}{c}x\\y\end{array}\right]

B= \left[\begin{array}{c}4\\2\end{array}\right]

i.e, AX=B

or X= A⁻¹ B

A⁻¹ = 1/|A| * Adj A

determinant of A = |A|= (7*-6) - (-4*10)

                                    = (-42)-(-40)

                                    = (-42) + 40 = -2

so, |A| = -2

Adj A=  \left[\begin{array}{cc}-6&4\\-10&7\end{array}\right]

A⁻¹ =  \left[\begin{array}{cc}-6&4\\-10&7\end{array}\right]/ -2

A⁻¹ =  \left[\begin{array}{cc}3&-2\\5&-7/2\end{array}\right]

X= A⁻¹ B

X=  \left[\begin{array}{cc}3&-2\\5&-7/2\end{array}\right] *\left[\begin{array}{c}4\\2\end{array}\right]

X= \left[\begin{array}{c}(3*4) + (-2*2)\\(5*4) + (-7/2*2)\end{array}\right]

X= \left[\begin{array}{c}12-4\\20-7\end{array}\right]

X= \left[\begin{array}{c}8\\13\end{array}\right]

x= 8, y= 13

solution set= (8,13).

Option b is correct.

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3 years ago
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seropon [69]

Answer:

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